pointintime said:
-2^-1 t3^2 - 180 s (t3) + t3^2 = a^-1 (Vo (180 s) - 1100 m + Xo)
(Vo (180 s) - 1100 m + Xo)^-1 a(-2^-1 t3^2 - 180 s (t3) + t3^2) = 0
:O
pointintime said:
-2^-1 t3^2 - 180 s (t3) + t3^2
ok how do I combine
-2^-1 t3^2
and
t3^2
:O
Okay, don't take this the wrong way, but you really need to brush up on some basic algebra.
Let's write out your equation a little more clearly. We start with:
-2^-1 t3^2 - 180 s (t3) + t3^2 = a^-1 (Vo (180 s) - 1100 m + Xo)
Now first of all, do you know that any number to the power -1 is just the reciprocal of that number? There's no reason to write "-2^-1" -- that's just -1/2. Same with a^-1 -- that's just 1/a. So let's start with:
-1/2 t3^2 - 180 s (t3) + t3^2 = 1/a (Vo (180 s) - 1100 m + Xo)
Now, you need to identify the terms, that is, the quantities that are being added or subtracted. Those are the ones that you can "move" to the other side of the equal sign by adding or subtracting them from both sides. You have three terms on the left side and one term on the right side. We'll get them all on the left side by subtracting the right side from both sides of the equation. That gives us:
-1/2 t3^2 - 180 s (t3) + t3^2 - 1/a (Vo (180 s) - 1100 m + Xo) = 0
Follow that?
Now, you need to identify the terms with t3^2, with t3, and with no t3 at all. There are four terms on the left side now, but we should not have more than three, so you must find two that have the same power of t3 and add them.
You identified the two terms that have t3^2 in the second quote above. Now that I've rewritten them as -1/2 t3 and t3^2, can you combine them? You have one t3^2 and you're adding a negative 1/2 t3^2, which is the same as subtracting 1/2 t3^2.