MHB Understanding an Equation: $\frac {1}{2\sqrt{2}} = \frac{\sqrt2} {4}$

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SUMMARY

The equation $\frac {1}{2\sqrt{2}} = \frac{\sqrt2} {4}$ is established as valid through algebraic manipulation. By rationalizing the denominator of $\frac{1}{2\sqrt{2}}$, it can be rewritten as $\frac{\sqrt{2}}{4}$. This transformation is confirmed by expressing $\frac{1}{2\sqrt{2}}$ as $\frac{2}{4\sqrt{2}}$ and simplifying it to $\frac{\sqrt{2}}{4}$. Both methods demonstrate the equivalence of the two fractions.

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On the board, the professor made a note that:

$$\frac {1}{2\sqrt{2}}$$ is equal to

$$\frac{\sqrt2} {4}$$

I don't see how this is. Can someone explain this? I've tried to work it out a few ways.
 
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Note that

$$\frac{1}{2\sqrt{2}} = \frac{2}{4\sqrt{2}} = \frac{\left(\sqrt{2}\right)^2}{4\sqrt{2}} = \frac{\sqrt{2}}{4}$$
 
He rationalized the denominator:

$$\frac{1}{2\sqrt{2}}=\frac{1}{2\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{4}$$
 

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