Understanding Biot-Savart's Law for a Rotating Disc with Current Density

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SUMMARY

The discussion focuses on applying Biot-Savart's Law to a rotating disc with a current density σ, radius R, and angular velocity ω. Participants clarify the relationship between the angular velocity and the current density, specifically how the cross product results in the expression αr, where α is dependent on σ, r, and ω. The importance of accurately defining the area element dS' in terms of dr and dθ is emphasized to facilitate the evaluation of integrals necessary for calculating the magnetic field B. Clear diagrams and expressions are crucial for understanding the geometry of the problem.

PREREQUISITES
  • Understanding of Biot-Savart's Law
  • Familiarity with vector calculus, specifically cross products
  • Knowledge of angular velocity and current density concepts
  • Ability to perform integral calculus in polar coordinates
NEXT STEPS
  • Study the derivation of Biot-Savart's Law in detail
  • Learn about the application of vector calculus in electromagnetism
  • Explore the relationship between angular velocity and magnetic fields
  • Practice evaluating integrals in polar coordinates for similar problems
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Physics students, electrical engineers, and anyone studying electromagnetism, particularly those interested in the effects of rotating systems on magnetic fields.

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Homework Statement


There's a disc with a current density surface σ, with radius R and angular velocity ω
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Find the B

Homework Equations


α = vσ=ωrσ
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The Attempt at a Solution


I'm having problems understanding why the cross product gives αr
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## \vec{u_r} ## is a unit vector. The cross product ## \vec{\alpha} \times \vec{u_r} ## is simply ## \alpha \hat{z} ##. Write out the expression for ## dS' ## in terms of ## dr ## and ## d \theta ## and I think you will see where the "r" in the numerator comes from. Also, express ## \alpha ## in terms of ## \sigma ## and ## r ## and ## \omega ## . (## \alpha ## is not a constant). ## \\ ## editing... Your diagram is hard to read, but I see the disc extends out to radius R. (I initially thought the disc goes from ## R_1 ## to ## R_2 ##.) ## \\ ## Once you get these steps in place, you can then evaluate the integrals.
 
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