Understanding Body Diagonals of a Cube

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SUMMARY

The body diagonals of a cube are defined as the line segments connecting opposite corners of the cube. The angle between these body diagonals is consistently 90 degrees, as they bisect each other. To calculate the angle using the dot product, one must represent the diagonals as vectors. A common approach involves using a unit cube with coordinates such as (0, 0, 0) to (1, 1, 1) for one diagonal and (0, 0, 1) to (1, 1, 0) for the other diagonal.

PREREQUISITES
  • Understanding of vector mathematics and the dot product
  • Familiarity with 3D geometry, specifically cubes
  • Knowledge of coordinate systems in three dimensions
  • Ability to visualize geometric shapes and their properties
NEXT STEPS
  • Study vector representation of geometric shapes in 3D space
  • Learn how to apply the dot product to find angles between vectors
  • Explore the properties of cubes and their diagonals in geometry
  • Investigate the concept of bisectors in three-dimensional figures
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Students of mathematics, geometry enthusiasts, and anyone studying vector calculus or 3D modeling will benefit from this discussion.

Disar
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Can anyone out there tell me what the body diagonals of a cube are.
I am asked to find the angle between the body diagonals of a cube. Seeing as how it is just the application of the dot product it does not seem difficult other than I do not know what body diagonals are (I have an idea but would like to know from someone for sure).
 
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Found it! The body diagonals of a cube are the from one point on a cube to the next and the angle between them is 90 degrees (they bisect one another)
Should of looked first
 
I have the same problem, yet, I still can't picture it.
 
slice the cube through the intersecting diagonal... the shape that is left is like an "incline plane". or imagine a table with square top, and square sides and square base with the legs intersecting.
 
overseastar said:
I have the same problem, yet, I still can't picture it.
It's the thing in these pictures:

http://library.thinkquest.org/22494/images/cubi.jpg

http://www.mathaware.org/mam/00/master/essays/B3D/2/JPG/figure16.jpg

In the second picture, it's the "longer diagonal".
 
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I seem to be getting an answer of 45 degrees which isn't right...
 
When drawing the vectors in the case within the cube, do they have to be from the same origin?
 
nvm, thanks for your help~!
 
Did you get the correct answer?
 
  • #10
i used a unit cube.
with one diagonal at (0 0 1) (1 1 0)
the other diagonal at (0 0 0) (1 1 1)
but it doesn't work, hmmm...for a sec i thought i did get it.
 
  • #11
overseastar said:
i used a unit cube.
with one diagonal at (0 0 1) (1 1 0)
the other diagonal at (0 0 0) (1 1 1)
Good, now find the vectors describing the diagonals using the vectors given above, representing their end-points.

but it doesn't work, hmmm...for a sec i thought i did get it.
What do you mean by "it doesn't work"? What doesn't work?

The answer written by Disar is incorrect.
 
  • #12
oh, if that's the case, I think I got it LOL Thanks a bunch!
 
  • #13
I went to my professor about this problem and he told me to use A=x+y+z and B= -x+y+z, naming one of the body diagonals A, and the other body diagonal B. I'm a bit confused how to take the 4 points above to make them fit the A and B my prof gave me. Can anyone help me with this please?? Thanks
 
  • #14
Gokul43201 said:
Good, now find the vectors describing the diagonals using the vectors given above, representing their end-points.

What do you mean by "it doesn't work"? What doesn't work?

The answer written by Disar is incorrect.

Can you help me? I still don't get it, thanks
 

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