Understanding Circular Orbits and Central Forces and Explanation

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The discussion focuses on a classical mechanics problem involving a particle of mass "m" moving under an attractive central force described by F=k/r^5, where k is negative. To demonstrate that the particle's orbit is circular and passes through the force center, it is essential to establish that the attractive force must conform to the specified form. The approach involves determining equilibrium points and analyzing potential energy, with the minimum potential energy occurring at r=0, which leads to infinity. Additionally, the relationship between the particle's distance r and the polar angle θ is crucial for deriving the force function. Understanding how different central forces influence orbital shapes is also a key point of inquiry.
fahd
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central forces-please chek answer!

hello...
i have this question in my classical mechanics book and was wondering if some one could help me?

the question says that there is a particle of mass "m" that is moving under an attractive central force F=k/r^5 where k<0
show that the particles orbit is circular and this particle aslo passes through the force centre?


Answer) what i did was that i said that in order for the orbit to be circular, the minimum potential ebergy should be equal to the total energy at that point,,
finding the equilibrium points, the only equilibrium point that made the potential energy minimum was r=0 and this value gave the minimum value of p.e as infinity...is this approach right! please help...also please tell me how do we know which central force leads to what kind of an orbit!
please replyn soon..
thanks!
 
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Fahd, One way to do this, is to show that for a particle to move in a circular orbit passing through the force center, the attractive force must be of the form k/r^5.

If the particle is moving in a circle of radius R passing through the force center , then the distance of the particle r to the force center as a function of \theta will be r=2R \cos\theta (From the property that an angle in a semicircle is a right angle) where \theta is the polar angle

Once you have this relation, can you figure out how you can find the Force as a function of r? (Hint: Try using the differential equation which relates u and F where u=\frac{1}{r} and F is the force.

If you solve for F, you will get F as k/r^5.
 
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