Understanding Complex Numbers for Solving Problems

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Homework Help Overview

The discussion revolves around solving a problem involving complex numbers, specifically focusing on the equation g(z) = z, where z is expressed in terms of real and imaginary components.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore different algebraic manipulations to isolate z, with some questioning their steps and others providing insights on using the conjugate to simplify expressions.

Discussion Status

The discussion has progressed with participants sharing their attempts and corrections. Some have successfully arrived at a solution, while others express uncertainty about their methods. There is a collaborative atmosphere with participants offering tips and affirmations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use.

meee
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need a lil help here

thnx
 
Last edited:
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Set g(z)=z, that is, write 2 + zi = z and then solve for z.
 
ok.. thanks, any tips in solving for z?

i got.. z = 2 + zi
z/z = 2/z + i
1 = 2/z + i
2/z = 1 - i
z= 2/(1-i)

dont think I am going the right way
 
Last edited:
[tex]2 + iz = z[/tex]
[tex]2 = z -iz = z(1-i)[/tex]

and so, like you have

[tex]z= \frac{2}{1-i}[/tex]

now multiply by the conjugate of the denominator on top and bottom
 
wel... we can divide 2 by (1 - i) to get z...OHHHhhhhhhhhhhhhhhhhhhhh ahhhhhhhhhh.!1 forgot that!1 multiple by conjugate... how silly of me

thankyou so much! !1

yaaay...

bottom: (1-i) * (1+i) = 2
top: 2*(1+i) = 2+2i

= (2+2i)/2
= 1+i

Yayaya Thnnx So mUcH!
 
Last edited:
[tex]z= \frac{2}{1-i} =\left( \frac{2}{1-i}\right) \left( \frac{1+i}{1+i} \right) = \frac{2(1+i)}{(1-i)(1+i)} = \frac{2(1+i)}{1^2-i^2} = \frac{2(1+i)}{1-(-1)} = 1+i[/tex]
 
nice diagram!

tankyou somuch
 

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