GJ1
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This was not a homework assignment, it's not necessary to understand the equation for this course, I was just interested in how they derived their answer.
The discussion revolves around solving a circuit equation involving complex numbers, specifically the expression [50/(4+j3)(50)+100] x 150. Participants are attempting to clarify the manipulation of complex numbers in the context of electrical current calculations.
Participants do not reach a consensus on the correct interpretation of the equation or the calculations leading to the final answer. Multiple competing views remain regarding the manipulation of complex numbers and the structure of the original expression.
Participants highlight the ambiguity in the original mathematical expression, noting that the lack of clear parentheses leads to confusion in interpretation and calculation. There is also a recognition that some participants may need to improve their understanding of complex numbers.
This discussion may be useful for students learning about complex numbers in electrical engineering or physics, particularly those who are encountering these concepts for the first time and seeking clarification on their application in circuit analysis.
I should have said that we are only supposed to give hints and directions in a homework type of question. I think you should give it another try using the hint in my post #30 above.GJ1 said:This was not a homework assignment, it's not necessary to understand the equation for this course, I was just interested in how they derived their answer.
Although you have parentheses and brackets in your work, you don't have enough of them.Babadag said:50/[(4+3j)x50+100]x150=20-10j
And yet:Mark44 said:50/[(4+3j)x50+100]x150 means this:
$$\frac{50}{(4 + 3j) \cdot 50 + 100} \cdot 150$$
The above equals $$\frac {7500}{(4 + 3j) \cdot 50 + 100}$$
and does not equal 20 - 10j.
He doesn't. He gets 50/(2+j) from 150/( (4+j3)+2 ).GJ1 said:Can you just explain how you get 50/2+j from 150/(4+j)+2
I stand corrected.PeroK said:And yet:
$$\bigg [\frac{50}{(4 + j3)(50) + 100} \bigg ] \times 150 = \frac{150}{(4 + j3) + 2}= \frac{50}{2+ j} = \frac{(50)(2 - j)}{5} = 20 - j10 $$
UnderstoodFactChecker said:He doesn't. He gets 50/(2+j) from 150/( (4+j3)+2 ).
Please use parenthesis to make your math expressions clear.
This is not just a picky complaint. In these days of computers and calculators, they will always give you the wrong answer if the parenthesis are wrong.
And now the OP has what he wanted. A solution on a plate!Mark44 said:I stand corrected.
Right. But it won't go very far unless the OP has learned from this thread. Still, we should be careful to not give in to frustration and just give the answer.PeroK said:And now the OP has what he wanted. A solution on a plate!
We could give them a similar complex number manipulation question to test their understanding. Any volunteers?FactChecker said:Right. But it won't go very far unless the OP has learned from this thread.
Those parentheses do not match up. You are missing a "closing paren" somewhere. I'm having a little trouble guessing what the 50 over (4+j3) represents. What about the second 50? Some units would be nice.GJ1 said:It's (50/(4+j3)(50)