# Using complex numbers to solve for a current in this circuit

Homework Helper
Gold Member
Can you just explain how you get 50/2+j from 150/(4+j)+2
He doesn't. He gets 50/(2+j) from 150/( (4+j3)+2 ).

This is not just a picky complaint. In these days of computers and calculators, they will always give you the wrong answer if the parenthesis are wrong.

Last edited:
scottdave
GJ1
Just got it. Thanks for explaining it with your example. Greatly appreciated!!!!!

FactChecker and berkeman
Mentor
And yet:
$$\bigg [\frac{50}{(4 + j3)(50) + 100} \bigg ] \times 150 = \frac{150}{(4 + j3) + 2}= \frac{50}{2+ j} = \frac{(50)(2 - j)}{5} = 20 - j10$$
I stand corrected.

GJ1
He doesn't. He gets 50/(2+j) from 150/( (4+j3)+2 ).

This is not just a picky complaint. In these days of computers and calculators, they will always give you the wrong answer if the parenthesis are wrong.
Understood

FactChecker and berkeman
Homework Helper
Gold Member
2022 Award
I stand corrected.
And now the OP has what he wanted. A solution on a plate!

Homework Helper
Gold Member
And now the OP has what he wanted. A solution on a plate!
Right. But it won't go very far unless the OP has learned from this thread. Still, we should be careful to not give in to frustration and just give the answer.

Mentor
Right. But it won't go very far unless the OP has learned from this thread.
We could give them a similar complex number manipulation question to test their understanding. Any volunteers?

FactChecker