Understanding Complex Numbers: Formulas and Applications

Click For Summary

Homework Help Overview

The discussion revolves around finding a formula for the values of m such that \( z^m = z \), where \( z \) is defined as \( \cos(7\pi/6) + i\sin(7\pi/6) \). Participants are exploring the implications of using De Moivre's theorem in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to derive the relationship between m and k using equations derived from De Moivre's theorem. Questions arise regarding the correctness of their derived formulas and the conditions under which m can be an integer.

Discussion Status

There is an ongoing exploration of the relationships between m and k, with some participants noting discrepancies in their calculations. Guidance is being offered regarding the integer nature of m and its dependence on k.

Contextual Notes

Participants are discussing the requirement that m must be an integer, which leads to further questioning about the values of k and their implications on m.

Dousin12
Messages
43
Reaction score
0
1. Give a formula for the values on m such that z^m=z

z=cos(7pi/6)+i*sin(7pi/6)

2. If i use de movires i get

3. m*7pi/6=7pi/6 + k*2pi

But then i get the value that k=12/7, Which is the wrong formula.

The correct answer is 1+12k for k=0,1,2...
 
Physics news on Phys.org
Dousin12 said:
1. Give a formula for the values on m such that z^m=z

z=cos(7pi/6)+i*sin(7pi/6)

2. If i use de movires i get

3. m*7pi/6=7pi/6 + k*2pi

But then i get the value that k=12/7, Which is the wrong formula.

The correct answer is 1+12k for k=0,1,2...
What happened to m in your answer?

Can you show us your work ?
 
m*7pi=7pi+k*12pi
m=1+12k/7

Okay, i got closer to the right answer now

Which is the equation wolfram alpha also get if i post my original equation. So it must be something wrong!

1+12k is the correct!
 
Dousin12 said:
m*7pi=7pi+k*12pi
m=1+12k/7

Okay, i got closer to the right answer now

Which is the equation wolfram alpha also get if i post my original equation. So it must be something wrong!

1+12k is the correct!
You have ##\ m=1+\frac{12}{7}k\,,\ ## & k must be some integer. I suppose from the context of the question that m must also be an integer.

m will only be an integer if k is an integer multiple of 7 , Right ?

let k = 7n .
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
Replies
18
Views
7K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
11K
Replies
2
Views
6K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
8
Views
1K
Replies
39
Views
6K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K