Understanding current measurement on an irregular waveform

In summary, the conversation discusses using a Keithley 2400 source meter to generate a 120Hz AC signal for resistance measurements on semiconductor materials. The Keithley 2000-20 multimeter is used to validate the input current, with a 1.01 ohm resistor and a sweep from 1A to -1A. The meter measures .94A during the sweep and 1.01A when sending 1A without sweeping. The difference in magnitude and the impact of using an AC current are questioned, as well as the presence of dwells at 0A and a 7% error. There is also a request to set the source to a 2App square wave with a -1A offset.
  • #1
tempneff
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I hoped to use a Keithley 2400 source meter to generate a ~120Hz AC signal by outputting a 2-point sweep from 1A to -1A on an infinite trigger. The waveform image is attached below.

The end goal is a resistance measurement for bulk semiconductor materials, we prefer AC measurement to avoid thermoelectric drifts. To validate my input current I am measuring AC amperage through a verified 1.01 ohm resistor with a Keithley 2000-20 multimeter.

The meter measures .94A AC during the sweep. If I send 1A without sweeping and read DC current, it measures 1.01A; as expected.

I'd like to better understand the difference in magnitude. How is the measurement impacted by an "AC" current. Is there something problematic math-wise by not sending a sine wave.

current_waveform.PNG
 

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  • #2
Why are there dwells at 0A when switching polarity? Is that maybe where the 7% error is coming from?
 
  • #3
Could be. I think it is inherent to the timing of the source meter. I have the delay set to zero, but we know that isn't possible.
 
  • #4
Is there a way to set the source to be 2App square wave with a -1A offset, instead of it being the two point sweep? I'm not familiar with that generator...
 

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