Understanding Derivatives: Real-World Application Examples

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    Confusion Derivative
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Discussion Overview

The discussion revolves around understanding the concept of derivatives, particularly in the context of real-world applications such as the ladder problem. Participants explore the meaning of derivatives, their interpretation as rates of change, and their graphical representation.

Discussion Character

  • Conceptual clarification, Technical explanation

Main Points Raised

  • One participant expresses confusion about the meaning of derivatives in real-world applications, specifically questioning why certain rates, like dx/dt = 2 ft/sec, are given as derivatives.
  • Another participant defines the derivative as the limit of a ratio, indicating that dx/dt typically represents a distance over time.
  • A different participant describes the derivative as the rate of change at an instant, likening it to speedometers on the corners of the ladder in the problem.
  • Another contribution reiterates that the slope of a graph, representing change in y over change in x, corresponds to the derivative when the axes are defined in feet and seconds.

Areas of Agreement / Disagreement

Participants generally agree on the definition of derivatives as rates of change and their relationship to the slope of a tangent line on a graph. However, there is no consensus on the participant's initial confusion regarding the application of derivatives in specific problems.

Contextual Notes

The discussion highlights a lack of clarity regarding the interpretation of given rates in applied problems and the conceptual understanding of derivatives as limits and slopes.

Iron_Brute
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I'm not sure if this should go in this section or the homework section but I'm having a problem fully understanding what a derivative means in a real world application. My class started moving into basic application problems but I'm not sure what the derivative means. An example of what I mean is a ladder problem in my cal book.
A ladder at 90 degress is sliding horizontally at 2 ft/sec, and in the solution section it says that dx /dt = 2 ft/sec is a given but I don't know why that is a given. In the other example problems any numbers that are "going at a rate of" the solution in the text is saying that that number is the derivative with respect to time, but I don't understand why and can't conceptually understand what that means

The way I understood derivative is that it is the slope of tangent line. So if anyone could explain this to me I'd really appreciate it.
 
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The derivative is the limit of a ratio
dx/dt=2 ft*sec^-1
usually means x is a distance and t is a time.
 
Derivative is the rate of change over an instant of time (hence it's a limit). On the ladder problem, it would be like little speedometers on the corners of the ladder. If you graphed height of latter vs. time, say, the speedometer at any time during the fall comes out the same as the slope of the tangent line on graph at any fixed point in time.
 
Last edited:
Recall the slope of a graph is the change in y / change in x. Thus, if the graph axes are feet and seconds then change in feet / change in seconds is the slope or as more colloquially known in calculus, derivative.
 

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