Understanding Destructive Interference in Electron Wave Functions

Click For Summary
Destructive interference in electron wave functions occurs due to the complex nature of wave functions, which can take on negative values as probability amplitudes. While the probability itself, represented by the square of the wave function, cannot be negative, the interference pattern results in variations in probability density across different locations. The discussion highlights the dual nature of electrons as both particles and waves, emphasizing that the context of interaction determines which model is more applicable. In scenarios like the double-slit experiment, destructive interference does not destroy the particle but alters the probability distribution of its detection. Understanding these concepts is crucial for interpreting quantum mechanics and its implications for particle behavior.
jalebi
Messages
24
Reaction score
0
Hi guys,

I have a question regarding electron wave functions. If an electron's wave function describes the probability of it being at a specific position, how can two wave functions destructively interfere (as occurs in the formation of anti-bonding atomic orbitals)? I can understand how the wave functions (essentially probability density functions, right?) can interfere constructively since the individual probabilities are summed together. But in destructive interference, does one wave function have negative probability? I can't see how else destructive intereference of electron wave functions occurs.
 
Physics news on Phys.org
The wave function is not a probability, it's a probability *amplitude*. The crucial fact about quantum mechanics is that it must be described in terms of a complex quantity , which indeed can be negative, causing destructive interference. The probability itself is |Ψ|2, which cannot be negative.
 
Last edited:
Ah okay, so the wavefunction squared is the actual probability.

I suppose it's probably best to just consider electron = wave function. The only problem I have with that is that sometimes you have to stop considering electron = wave function and go back to electron = particle (e.g. instantaneous dipoles). At what point do you go from the quantum approach to the "an electron is a particle that moves like a wave" approach?
 
So every particle 'darkens' an area of the screen in a double-slit experiment? Because if the particle were a wave and it destructively interfered, wouldn't that destroy the particle?
 
jalebi said:
Ah okay, so the wavefunction squared is the actual probability.

I suppose it's probably best to just consider electron = wave function. The only problem I have with that is that sometimes you have to stop considering electron = wave function and go back to electron = particle (e.g. instantaneous dipoles). At what point do you go from the quantum approach to the "an electron is a particle that moves like a wave" approach?

It depends on what the electron is interacting with, and how close are the electrons to other electrons. In particle accelerators, for example, the charged particles are often far apart enough that their individual wavefunctions don't overlap. So in such a case, they are often treated as classical particles.

A QM treatment of this interference can be found in the Marcella paper.

http://arxiv.org/ftp/quant-ph/papers/0703/0703126.pdf

Zz.
 
StevieTNZ said:
So every particle 'darkens' an area of the screen in a double-slit experiment? Because if the particle were a wave and it destructively interfered, wouldn't that destroy the particle?

It would indeed destroy the particle if the only thing the particle consisted of was the wave in the equation. One major criticism directed at the sole use of the wave equations in association with particles which arose when the de Broglie relations were considered was that the wave very rapidly disperses (according to the equation) and the energy becomes non-localized. In other words, there's nothing in the model to account for the fact that the particle's energy is held together in a localized region.
 
Last edited:
StevieTNZ said:
So every particle 'darkens' an area of the screen in a double-slit experiment? Because if the particle were a wave and it destructively interfered, wouldn't that destroy the particle?

No, why? Neither light nor quantum mechanical waves are destroyed by "destructive interference". It's the intensity/probability that is 'destroyed' in that particular location - and compensated for by a greater intensity/probability somewhere else.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
8K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 27 ·
Replies
27
Views
3K
Replies
15
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K