BOAS
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Hello,
these are the first differential equations I've tried to solve...
Find the general solution of the following differential equations. In each case if
y = 2 when x = 1 find y when x = 3.
[itex]2x \frac{dy}{dx} = 3[/itex]
[itex]2x \frac{dy}{dx} = 3[/itex]
[itex]\frac{dy}{dx} = \frac{3}{2x}[/itex]
[itex]dy = (\frac{3}{2x}) dx[/itex]
[itex]\int dy = \int (\frac{3}{2x}) dx[/itex]
[itex]y = \frac{3}{2}ln|x| + c[/itex]
Firstly, is this correct and secondly, the question says that when y = 2, x = 1 but ln(1) = 0 so I don't see how this can be true. Or have I just found out that my constant of integration, c = 2?
Thanks for any help you can give!
BOAS
these are the first differential equations I've tried to solve...
Homework Statement
Find the general solution of the following differential equations. In each case if
y = 2 when x = 1 find y when x = 3.
[itex]2x \frac{dy}{dx} = 3[/itex]
Homework Equations
The Attempt at a Solution
[itex]2x \frac{dy}{dx} = 3[/itex]
[itex]\frac{dy}{dx} = \frac{3}{2x}[/itex]
[itex]dy = (\frac{3}{2x}) dx[/itex]
[itex]\int dy = \int (\frac{3}{2x}) dx[/itex]
[itex]y = \frac{3}{2}ln|x| + c[/itex]
Firstly, is this correct and secondly, the question says that when y = 2, x = 1 but ln(1) = 0 so I don't see how this can be true. Or have I just found out that my constant of integration, c = 2?
Thanks for any help you can give!
BOAS