Understanding Differentiation with x: ln and Exponents

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Homework Statement



1) ln { (x^2+x+1) / ( x^2-x+1) } here ln = natural log
2) x^2+x^(2y)=c here c=constant


Homework Equations





The Attempt at a Solution

 
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Mark44 said:
Show us your attempt at a solution.

My attempt at 2)

x^2+x^(2y)=c

x^2+2ylnx=c

diff wrt x

2+(2lnx+1/x.2y.y')=0

1/x.2y.y'=-2-2lnx

y'= -2(lnx+1)x / 2y

is this correct and i can't understand the question no. one and how to start it's differentiation.
 
M.Qayyum said:
My attempt at 2)

x^2+x^(2y)=c

x^2+2ylnx=c
x2y [itex]\neq[/itex] 2y ln(x).

You can write x2y as (eln(x))2y = e2y ln(x), and then differentiate.

For #1, ln(a/b) = ln(a) - ln(b). Use that property of logs before trying to differentiate.
M.Qayyum said:
diff wrt x

2+(2lnx+1/x.2y.y')=0

1/x.2y.y'=-2-2lnx

y'= -2(lnx+1)x / 2y

is this correct and i can't understand the question no. one and how to start it's differentiation.
 
Thank u very much...it really helps