Understanding Differentiation with x: ln and Exponents

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Homework Help Overview

The discussion revolves around differentiation involving natural logarithms and exponents, specifically focusing on two equations: one involving the natural logarithm of a rational function and another involving a relationship between variables and a constant.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants share their attempts at differentiating the given equations, with some expressing confusion about the first problem and how to initiate differentiation. There are discussions about the properties of logarithms and how to apply them in the context of differentiation.

Discussion Status

Some participants have provided guidance on using logarithmic properties to simplify the differentiation process. There is an ongoing exploration of different interpretations and methods for tackling the problems, but no consensus has been reached regarding the correctness of the approaches presented.

Contextual Notes

Participants note the need for clarification on the differentiation of the first problem and the proper application of logarithmic identities in the second problem. There is also mention of potential misunderstandings regarding the manipulation of terms in the equations.

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Homework Statement



1) ln { (x^2+x+1) / ( x^2-x+1) } here ln = natural log
2) x^2+x^(2y)=c here c=constant


Homework Equations





The Attempt at a Solution

 
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Show us your attempt at a solution.
 
Mark44 said:
Show us your attempt at a solution.

My attempt at 2)

x^2+x^(2y)=c

x^2+2ylnx=c

diff wrt x

2+(2lnx+1/x.2y.y')=0

1/x.2y.y'=-2-2lnx

y'= -2(lnx+1)x / 2y

is this correct and i can't understand the question no. one and how to start it's differentiation.
 
M.Qayyum said:
My attempt at 2)

x^2+x^(2y)=c

x^2+2ylnx=c
x2y [itex]\neq[/itex] 2y ln(x).

You can write x2y as (eln(x))2y = e2y ln(x), and then differentiate.

For #1, ln(a/b) = ln(a) - ln(b). Use that property of logs before trying to differentiate.
M.Qayyum said:
diff wrt x

2+(2lnx+1/x.2y.y')=0

1/x.2y.y'=-2-2lnx

y'= -2(lnx+1)x / 2y

is this correct and i can't understand the question no. one and how to start it's differentiation.
 
Thank u very much...it really helps
 

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