Understanding Empirical Formulas & Ions: 2 Questions Answered

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Discussion Overview

The discussion revolves around understanding empirical formulas and the formation of ions, specifically focusing on how to write empirical formulas for elements like aluminum (Al) and the ionic behavior of barium (Ba) and phosphorus (P). The scope includes conceptual clarification and technical explanation regarding chemical formulas and ion formation.

Discussion Character

  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • One participant asks how to write the empirical formula for aluminum and in general, noting that empirical formulas represent the simplest ratio of atoms in a compound.
  • Another participant explains that for the compound C2H6, the empirical formula is CH3, and states that the empirical formula for aluminum is simply Al.
  • A different participant clarifies that the formation of cations or anions does not depend solely on the number of electrons in an atom, indicating that barium, being a metal, will lose electrons to form a cation, while phosphorus, a non-metal, will gain electrons to form an anion.
  • One participant seeks further clarification on how to determine which elements are likely to lose or gain electrons, asking if there is a rule for this.
  • Another participant suggests that consulting the periodic table is sufficient for understanding the properties of elements regarding electron loss or gain.

Areas of Agreement / Disagreement

Participants generally agree on the definitions of empirical formulas and the behavior of metals and non-metals in terms of electron transfer. However, there is no consensus on a specific rule for determining which elements lose or gain electrons, as this remains an area of inquiry.

Contextual Notes

Some assumptions regarding the understanding of empirical formulas and ionic behavior are not explicitly stated, and the discussion does not resolve the nuances of electron transfer rules.

omni
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2 Questions please

hello.
i need help to Understand how can i Write Empirical formula for Al or in general how to Write Empirical formula?

2)i also need help to Understand how can i know what Ion i will get from Ba and P ?



i think for ba is will be Negative because there more Electron. but i doesn't understand it very well.

hope u can help me.
thanks :).
 
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Empirical formula is the simplest ratio of number of atoms in the compound.
For a compound C2H6, the empirical formula is CH3
Al is a single atom. Its empirical formula will be same i.e. Al
 


Formation of cation or anion does not depends on the number of electrons in atom. As Ba is metal it has property to lose electron. It will form cation while P is non-metal is accept electron. It will form anion.
 


hi thanks for ur Answers but i mean Al and N Together.

In General how can i know what element is property to lose electron and what element is accept electron ?

there is any rule for it?
thanks.
 


omni said:
hi thanks for ur Answers but i mean Al and N Together.

Al and N what?

In General how can i know what element is property to lose electron and what element is accept electron ?

there is any rule for it?

It is enough to consult periodic table.
 


ok i Understand.

thanks to all.
 

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