Understanding Energy Conservation in a Hanging Spring System

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Homework Statement



Scenario: A block of mass m hanging on the end of a vertical spring with spring constant k

Homework Equations



When the spring has come to rest:

Vertical eqm: weight = force exerted by spring
mg = kx

Energy conservation: loss in GPE = gain in EPE of spring
mgx = 0.5*kx^2

The Attempt at a Solution



canceling x on both sides of the energy conservation equation will give me mg = 0.5*kx, which does not tally with the equation of vertical equilibrium. Why is this so?

Is there a problem with my understanding of energy conservation?
 
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hi divineyang! :smile:

(try using the X2 icon just above the Reply box :wink:)
divineyang said:
When the spring has come to rest:

Vertical eqm: weight = force exerted by spring
mg = kx

Energy conservation: loss in GPE = gain in EPE of spring
mgx = 0.5*kx^2

canceling x on both sides of the energy conservation equation will give me mg = 0.5*kx, which does not tally with the equation of vertical equilibrium. Why is this so?

Is there a problem with my understanding of energy conservation?

yes, you've lost your bounce! :biggrin:

if there's conservation of energy, then the weight will go speeding past the equilibrium position, and bounce happily up and down for ever and ever! o:)

(and zero speed doesn't mean zero acceleration! :smile:)
 
so I cannot use the energy conservation approach to find the displacement of the mass? other than equilibrium of forces, how else can I find the value of x?
 
i want to find the extension, x of a spring with spring constant k with a mass of m hanging on its end..

Express x in terms of k, m and g.

I want to know why its possible to derive an expression for x by using energy.
 
divineyang said:
i want to find the extension, x of a spring with spring constant k with a mass of m hanging on its end..

Express x in terms of k, m and g.

but what are the initial conditions? :confused:

if you want to use conservation (of anything), you need a before and an after …

if the question gives you an equilibrium position, but no initial position, then there's nothing to conserve, is there? :redface:

(and then you simply use ∑F = 0)
 
oh there arent any initial conditions haha. i understand now, thanks so much!