Understanding Energy Conservation in Quantized Angular Momentum Transitions

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SUMMARY

The discussion centers on energy conservation in quantized angular momentum transitions, specifically regarding atomic energy levels and photon interactions. The energy of an atom at the principal quantum number n=5 is -0.544 eV, while the energy of the emitted photon is 1.14 eV. The calculation of the atom's energy post-emission results in a value of 1.68 eV, leading to confusion as it does not correspond to an integer quantum number. The correct interpretation of quantum states is crucial to avoid miscalculations in energy transitions.

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  • Understanding of quantum mechanics principles
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  • Experience with energy conservation laws in physics
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  • Study the concept of quantized energy levels in hydrogen-like atoms
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Homework Statement
42.15 A hydrogen atom is it its 5th excited state. The atom emits a 1 090 nm wavelength photon. Determine the maximum possible orbital angular momentum of the electron after emission.
Relevant Equations
En = -13.606/h^2
E = hf
I don’t understand how energy is conserved here. The energy of the atom when n=5 is -.544eV. The energy of the photon is 1.14eV. After release, the energy of the atom is -.544 - 1.14 = 1.68eV. Using this value, I get n = 2.67, not an integer, so n = 3 and the atom has energy = -1.51 eV. I have the right answer but am missing something basic.
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It's easy to slip up by taking n = 5 to correspond to the 5th excited state.
 
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TSny said:
It's easy to slip up by taking n = 5 to correspond to the 5th excited state.
It sure was!
 
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