Understanding Far Points and Lens Power in Correcting Myopia

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The discussion revolves around calculating the far point of a nearsighted person without contact lenses and determining the lens power needed for full myopia correction. The individual currently uses contact lenses with a power of -2.00 diopters and has a far point of 10.0 meters during a vision test. To find the far point without lenses, one must consider the relationship between the lens power and the far point distance. The required lens power for correction can be derived using the lens formula and the known far point. Understanding these calculations is essential for solving optics problems related to myopia correction.
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Homework Statement


While carrying contact lenses of D=-2.00 diopters, a nearsighted person takes a vision test and finds that his/her far point is 10.0m
a) what is the person's far point without contact lenses?
b) what lens power is required to correct the myopia fully?

Homework Equations


1/f = 1/o + 1/i
D=1/f

The Attempt at a Solution


This problem was for homework in our optics class, but I don't know how to start the problem. Its not like the usual problems I've been doing. Any help would be greatly appreciated.
 
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If you knew the far-point without correction, how would you determine the diopter value of the corrective lenses required?
How does the position of the far-point depend on the lenses used?
 
Do you know what the far point is?
 

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