Understanding Forces and Motion in a 3D Coordinate System

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The discussion centers on understanding the motion of a toy rocket engine attached to a puck gliding on a horizontal surface, specifically within a 3D coordinate system. Participants clarify that in this context, the XY plane is horizontal, with the Z-axis typically representing vertical motion. The confusion arises from the conventional labeling of axes, as the problem uses Y for horizontal motion rather than the expected vertical designation. It is emphasized that the puck's movement can involve both X and Y components, even if the force is horizontal. Overall, the conversation highlights the importance of understanding coordinate systems in analyzing forces and motion.
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Homework Statement



A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the xy plane. The 4.00-kg puck has a velocity of 3.00ˆi ms at one instant. Eight seconds later, its velocity is (8.00ˆi + 10.0ˆj) ms. Assuming the rocket engine exerts a constant horizontal force, find (a) the components of the force and (b) its magnitude.

Homework Equations



ΣF = m*a
a = ΔV/Δt

The Attempt at a Solution



Well, I took the all the info and applied it on the various formulas I know, and found the correct results, according to the book. So my problem doesn't lie there, as it's a simple problem of putting the correct quantities in the correct "positions". My problem lies more with "conceptualizing" the problem.

I also checked the manual, but I can't understand one thing: It says that the force that the engine exerts on the puck is horizontal, so I take it that means the X part of the XY axis', correct? So, if this force is horizontal, then how can he ask me about its component of the net force? Does the statement mean that it's not horizontal per se, just that it acts on the first quadrant? Apart from that, how does the puck develop a velocity at the Y/vertical plane?

From what I understand from the statement, it's a standard round puck on top of a, say floor, and I've put an engine on the back, that exerts a horizontal F force on it, causing it to move horizontally, but it somehow develops a velocity at both planes. Could anyone explain to me what exactly I'm missing?

Thanks!
 
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Darthkostis said:
I also checked the manual, but I can't understand one thing: It says that the force that the engine exerts on the puck is horizontal, so I take it that means the X part of the XY axis', correct? So, if this force is horizontal, then how can he ask me about its component of the net force? Does the statement mean that it's not horizontal per se, just that it acts on the first quadrant? Apart from that, how does the puck develop a velocity at the Y/vertical plane?
In this case the Y-axis is not vertical. The entire XY plane is horizontal. If a vertical direction were involved it would (likely) be designated Z.
 
gneill said:
In this case the Y-axis is not vertical. The entire XY plane is horizontal. If a vertical direction were involved it would (likely) be designated Z.

Ah, so it's as if I'm dealing with 3D object that slides on the ground. And the problem is using the X & Z axis' of the usual XYZ axis, just renaming the Z one Y. So technically, it's moving horizontally, but not in a straight line, it skews a bit to the side. Correct?
 
You've got the picture. The XY plane is generally taken to be horizontal when using a 3D XYZ coordinate system. Z is the usual designation for the vertical direction. X, Y, and Z are really just labels that we have come to use by convention.

We often use a 2D coordinate system to analyze motions that occur in a plane, such as typical projectile motion, and then we usually assign the X to the horizontal direction and Y to the vertical direction. But this is not strictly necessary. All those projectile motion equations could be written using X and Z instead of X and Y. Or, other letters or symbols could be assigned (UVW, for example). It's really just a matter of convention.
 
gneill said:
You've got the picture. The XY plane is generally taken to be horizontal when using a 3D XYZ coordinate system. Z is the usual designation for the vertical direction. X, Y, and Z are really just labels that we have come to use by convention.

We often use a 2D coordinate system to analyze motions that occur in a plane, such as typical projectile motion, and then we usually assign the X to the horizontal direction and Y to the vertical direction. But this is not strictly necessary. All those projectile motion equations could be written using X and Z instead of X and Y. Or, other letters or symbols could be assigned (UVW, for example). It's really just a matter of convention.

Got it. Yeah, I know the letters are interchangable, but I've not tackled 3D problems yet, so when I saw "horizontal" my mind went straight to the usual "X is horizontal, Y is vertical" concept.

Thanks for clearing this up for me!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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