Understanding geometry problem in relativity

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SUMMARY

The discussion focuses on the geometry problem related to relativity as presented in the document from Caltech. Specifically, participants seek clarification on the derivation of equation 2.4 from figure 2.3 and the disappearance of the term ##\Delta t^2##. The confusion arises from the use of geometric units where the speed of light, ##c##, is set to 1, which is not explicitly stated in the text. Participants express difficulty in understanding the second equality in equation 2.4, indicating a need for deeper exploration of the underlying concepts.

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  • Understanding of special relativity concepts
  • Familiarity with geometric units in physics
  • Basic knowledge of tensor calculus
  • Ability to interpret mathematical equations in physics
NEXT STEPS
  • Study the derivation of the metric tensor in general relativity
  • Learn about the implications of using geometric units in physics
  • Explore the relationship between spacetime intervals and geometry
  • Review the mathematical foundations of tensor calculus
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Students of physics, particularly those studying relativity, educators teaching advanced physics concepts, and researchers interested in the mathematical foundations of spacetime geometry.

Vrbic
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Homework Statement


It is not ordinary problem, it is connected to it. I don't understand a figure and how is described. The problem is here http://www.pmaweb.caltech.edu/Courses/ph136/yr2011/1102.2.K.pdf How did equation 2.4 from figure 2.3 arise? Why disappear ##\Delta t^2## from the right?
Another question is: In the text above eq.2.4 is written ##c\Delta t^2=\Delta t^2##?? Ok, if it says work in geometric units where ##c=1## ok, but it isn't mentioned.

Homework Equations


eq 2.4 ##\Delta s^2=-\Delta t^2+\Delta x^2+\Delta y^2=-(2h-\Delta y^2)+\Delta y^2##

The Attempt at a Solution


An attempt occurred in my mind, when I thought about it half an hour :-)

Thank you all.
 
Physics news on Phys.org
jedishrfu said:
So you figured it out?
No, second equality in 2.4 is out of me. ##-\Delta t^2+\Delta x^2+\Delta y^2=-(2h-\Delta y)^2 + \Delta y^2##
 

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