You have a serious error right at the start. You have, on the right, [itex](x+ y)^2[/itex] and you divide that by [itex]x^2[/itex] to get [itex](1+ y/x)^2= (1+ v)^2[/itex]
Up to there you are correct. But then your next line has [itex]1+ v^2[/itex] which is NOT the same thing. [tex](1+ v^2)= 1+ 2v+ v^2[/tex] which works nicely in canceling that "-2v" you will introduce.