Understanding Inverse Images and Continuity in Real Analysis

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SUMMARY

The discussion establishes that for any set S of reals, the relationship (f^-1 S)compliment = f^-1(S compliment) holds true. This property is crucial in proving that a function f is continuous if and only if the inverse image f^-1(S) is closed for every closed set S. Additionally, it is confirmed that f is continuous if for every open set U in the reals, the inverse image f^-1(U) is open. The discussion emphasizes the necessity of understanding the definitions of inverse images and continuity in real analysis.

PREREQUISITES
  • Understanding of inverse images in the context of functions
  • Familiarity with the concepts of open and closed sets in topology
  • Knowledge of continuity definitions in real analysis
  • Proficiency in delta-epsilon definitions of limits
NEXT STEPS
  • Study the properties of inverse images in more depth
  • Learn about the relationship between continuity and topological spaces
  • Explore the delta-epsilon definition of continuity in detail
  • Investigate examples of continuous functions and their inverse images
USEFUL FOR

Students and professionals in mathematics, particularly those studying real analysis, topology, or functional analysis, will benefit from this discussion.

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1. a) Show that (f^-1 S)compliment = f^-1(S compliment) for any set S of reals.


Then use part a) to show The function f is continuous iff f^-1(S) is closed for every closed set S.




2. inverse image = f^-1(S) = {x: f(x) [tex]\in[/tex] S}
f is continuous iff for every open set U [tex]\in[/tex] the reals, f^-1(U) is open.
 
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part a is true for any set, so you need to show f^-1(S^c) = (f^-1(S))^c,

so take x in f^-1(S^c), so f(x) is in S^c, so f(x) is not in S, so ...

for part b, what have you tried and what is your definition of continuous, delta/epsilon?
 

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