Understanding J Splitting in XPS

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SUMMARY

J splitting in X-ray Photoelectron Spectroscopy (XPS) occurs when an electron is emitted from the 2p orbital of an atom, such as argon, resulting in the formation of two distinct energy states: 2p3/2 and 2p1/2. This phenomenon arises due to the coupling of orbital angular momentum (l = 1) and spin angular momentum (s = 1/2), leading to total angular momentum states defined by j = |l - s| to l + s. The emitted electron has slightly less energy than the one in the 2p orbital, contributing to the observed doublet in XPS spectra.

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dgprakash
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Hi everyone, i have a doubt regarding XPS,

i read that a doublet is formed, for example in argon when an electron from 2p orbital leaves and leads to the formation of 2p 3/2 and 2p 1/2 states, and an electron with slightly lesser energy than one in the 2p orbital is emitted, giving rise to this doublet in XPS.

now what is this j splitting and how can 2p 3/2 and 1/2 states be formed, i.e what is the phenomenon happening there?

thanks in advance
 
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l = 1, s = 1/2, j = |l - s|, ..., l + s = 1/2, 3/2.

Hence you have j = 1/2, 3/2 with l = 1 (p). Thus you have terms of 2p1/2 and 2p3/2.
 
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