Understanding Joint Density Functions: Solving for Unknown Parameters

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Homework Help Overview

The discussion revolves around understanding joint density functions, specifically focusing on determining unknown parameters within a given joint density function defined by certain boundaries.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses confusion regarding the boundaries of the joint density function and seeks assistance in starting the problem. Some participants suggest that the total probability must equal one, while others provide feedback on the integration approach used to find the parameter 'a'.

Discussion Status

Participants are engaging in a constructive dialogue, with some providing guidance on the integration process and confirming the correctness of the original poster's calculations. There is an indication of further exploration needed regarding related topics such as marginal functions and covariance.

Contextual Notes

There are mentions of the original poster's uncertainty about statistics and a request for additional help on related sections of the problem, suggesting a need for further clarification on these topics.

wuid
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it seems that i can't understand the boundaries...
the joint density function:

f(u,v)= a , u^2 <= v <= 1
0 , else

find a

i just don't know how to start.
any help ?
thx
 
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welcome to pf!

hi wuid! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)

let's see :rolleyes: … that's a shelf of height a whose shape is a rectangle with a parabola cut out of it …

ok, you need it to have total probability of 1 :smile:
 
hi !
thx for the quick reply ,

let's see if i got u ,

\int^{1}_{-1}\int^{1}_{u^{2}}advdu=1

so a=\frac{3}{4}

is that right ?
 
looks good! :smile:
 
can you please guide me with two more section in this problem ,
related to marginal functions & covariance ?

and i'll leave you for good :)

i
 
i'm not much good at statistics :redface:

can you start a new thread? :smile:
 
o.k i'll start a new one later.

first i'll try harder... :)
 

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