Joint Probability Density Function

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Homework Help Overview

The problem involves a joint probability density function of two variables, X and Y, defined over specific ranges. The tasks include determining a constant for normalization, computing the marginal density function of Y, and finding the probability that X is less than Y.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to perform a double integral to find the normalization constant c, with some expressing uncertainty about the calculations involved. There are inquiries about how to compute the marginal density of Y and the probability P(X < Y).

Discussion Status

The discussion is active, with participants sharing their attempts at calculating the double integral and seeking clarification on the next steps for finding the marginal density and the probability. Some have made progress, while others are still grappling with the concepts involved.

Contextual Notes

Participants mention the requirement that the double integral of the joint density function must equal 1, and there is a reference to previous discussions regarding the marginal density of Y.

twoski
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Homework Statement



The joint probability density function of X and Y is given by
f(x, y) = c( x3 + xy/4 )

0 < x < 1
0 < y < 2

(a) For what value of c is this a joint density function?
(b) Using this value of c, compute the density function of Y .
(c) Using this value of c, nd PfX > Y g.

The Attempt at a Solution



I'm looking through my notes and i can't find anything that helps me solve A... :(
 
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The double integral, over the region, of the density function must be 1.
 
So the idea is, if i do a double integral on this function i should end up with c * some value, and i need to find a value for c such that c * some value = 1?
 
twoski said:
So the idea is, if i do a double integral on this function i should end up with c * some value, and i need to find a value for c such that c * some value = 1?

Try it yourself to see!
 
So i did it and i ended up with 3/4 * c... So the idea now is that i want C to equal 1?

And how would i start computing the density function of Y?
 
Last edited:
twoski said:
So i did it and i ended up with 3/4 * c... So the idea now is that i want C to equal 1?

And how would i start computing the density function of Y?

Do you not understand that you want the double integral = 1? That means that you need to equate your result to 1.

As to the density of Y: it will just be the *marginal* density of Y. The meaning of this was already dealt with in another thread.
 
Okay I've managed to figure out everything except for the last question. I have formulas for P( X ≤ x ) but it's asking me to find P( X < Y ).
 
twoski said:
Okay I've managed to figure out everything except for the last question. I have formulas for P( X ≤ x ) but it's asking me to find P( X < Y ).

Draw a picture of that region inside your given domain and integrate the joint density over it.
 

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