Understanding Kirchoff's Law and Solving Circuit Problems

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Pochen Liu
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Homework Statement


upload_2018-11-5_12-29-56.png

How do I calculate the current I3?

Homework Equations


I know that I1 = I2 + I3
and that I2 = 0.4

The Attempt at a Solution


So we have a voltage source of 3.7V I would've thought that the equation for a clockwise circuit be
0.4R2 - 3.7 - 200I3 = 0 which gives me an answer of -0.0183 when it should be 0.0187

How am I using the law wrong and how can I prevent doing so in the future?
 

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Pochen Liu said:
So we have a voltage source of 3.7V I would've thought that the equation for a clockwise circuit be
0.4R2 - 3.7 - 200I3 = 0 which gives me an answer of -0.0183 when it should be 0.0187

How am I using the law wrong and how can I prevent doing so in the future?
You need to pay attention to the direction of the currents as you do your "KVL walk" around the circuit. For example, ##I_3## is flowing down through ##R_3##, so as you "walk over" ##R_3## going clockwise around the circuit you'll see a rise in potential.
 
gneill said:
You need to pay attention to the direction of the currents as you do your "KVL walk" around the circuit. For example, ##I_3## is flowing down through ##R_3##, so as you "walk over" ##R_3## going clockwise around the circuit you'll see a rise in potential.
Is this because if I go 'walk over' instead of using the voltage it will add? since it's coming from the other direction, therefore I need to change it's mathematical sign around right?
 
Pochen Liu said:
Is this because if I go 'walk over' instead of using the voltage it will add? since it's coming from the other direction, therefore I need to change it's mathematical sign around right?
Right, you need to account for the current directions. If you "walk" in the same direction of the current you'll see a potential drop across the resistor. If you "walk" against the direction of the current you'll see a potential rise.
 
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