Understanding Limits: Solving Problems and Examples

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SUMMARY

This discussion focuses on solving limits in calculus, specifically addressing the problems lim\sum\limits_{k=1}^{n-1} \frac{k^{2}}{n^{3}} and lim\sum\limits_{k=2}^n \frac{k-1}{k!}. The first limit can be simplified by factoring out 1/n³ and utilizing the formula for the sum of squares, resulting in a limit of 1/3. The second limit is approached by breaking it into two separate sums, leading to a final answer of 1. These methods provide clear strategies for tackling similar limit problems.

PREREQUISITES
  • Understanding of calculus concepts, specifically limits.
  • Familiarity with summation notation and techniques.
  • Knowledge of the formula for the sum of squares: \(\sum_{k=1}^{n} k^2 = \frac{n(n+1)(2n+1)}{6}\).
  • Basic understanding of factorials and their properties.
NEXT STEPS
  • Study the properties of limits in calculus.
  • Learn about convergence and divergence of series.
  • Explore advanced summation techniques, including telescoping series.
  • Practice solving limits involving factorials and exponential functions.
USEFUL FOR

Students learning calculus, educators teaching limits, and anyone seeking to improve their problem-solving skills in mathematical analysis.

hamsterman
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I've been trying to learn some maths by myself. A book I found starts with a section on limits. I feel that I have a decent understanding of what is written, but then, there are some problems given that I just can't figure out. I feel like I'm missing something basic. I'm not sure what I'm looking for. Maybe a resource with some examples of how to solve different kinds of equations would be enough. I'd also appreciate it if you could show how to solve a couple of problems I'm having a hard time with:

[itex]lim\sum\limits_{k=1}^{n-1} \frac{k^{2}}{n^{3}}, n\geq 2[/itex]

and

[itex]lim\sum\limits_{k=2}^n \frac{k-1}{k!}, n\geq 2[/itex]
 
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For the first one, take 1/n3 outside the summation, the sum over k2 is readily available [ (n-1)n(2n-1)/6 ], so the limit will be 1/3.

For the second split it into two sums (k and -1 numerators). Compare them with each other. The final answer will be 1 (unless I made a mistake).
 
Thanks a lot, I see now.
 

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