Understanding Mass-Spring Behavior in Zero Gravity

Click For Summary
In a zero-gravity environment, a spring with an attached mass can still exhibit movement due to the potential energy stored in the spring when it is either stretched or compressed. When the mass is attached without any initial disturbance, the spring remains at its equilibrium position, and no oscillation occurs. However, if the mass is released from a position away from equilibrium, it will oscillate as the spring exerts a restoring force. Observing the energy transformations in the simulation, including kinetic and potential energy, provides further insight into this behavior. Understanding these dynamics clarifies that the spring's movement is not solely dependent on gravitational forces.
aatari
Messages
73
Reaction score
3
Hi Guys,

So I am using the following simulation for this activity (Mass and Springs).

The concept I need help with is to understand why when attaching a mass, the spring moves downward when the gravity is zero? If there is no gravity my limited understanding is that spring should not move.

Can someone please help me understand this phenomenon.

Thanks!

1. Homework Statement


How can you account for the behaviour of masses on springs when the force of gravity is zero? Give your answer both qualitatively (written explanation) and mathematically (algebraic explanation).

Homework Equations


[/B]
Fs = Fg
Fg = mg
Fs = k.x

The Attempt at a Solution

 
Physics news on Phys.org
When I went to the simulation website, it settled back to the dashed line for g=0. When you first hook it on, if you are not exactly on the equilibrium point then there will be some disturbance of the spring - note that you can use the hand to pull on the masses, then release and watch it oscillate.
If the spring is horizontal on a table, and you pull on it, you would expect it to exert a force back toward the equilibrium point.
 
  • Like
Likes aatari
If you attach the masses without stretching or compressing the spring, there is no oscillation.

If you attach the mass and release it away from the neutral point, it oscillates because you have provided some potential energy by stretching or compressing the spring.
 
  • Like
Likes scottdave and aatari
You guys are awesome. I actually took the spring disturbance as movement and this is obviously not the case. Using the ruler and dash line really helps. Thank you for the clarification.
 
Try turning on the energy bar graphs to watch how energy changes between different forms (kinetic, gravitational PE (if gravity), spring PE, and thermal (from the friction)). It is interesting to watch how the bar graphs respond.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
1K
  • · Replies 53 ·
2
Replies
53
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
4K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
2
Views
1K
Replies
23
Views
5K