Understanding Nested Quantifiers: How to Determine Truth Value | Help & Tips

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Homework Help Overview

The discussion revolves around understanding the truth value of a statement involving nested quantifiers in mathematics, specifically the expression Ax3y(x^2 < y + 1). Participants are exploring how to interpret and approach this problem.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of the quantifiers and the inequality involved. There are discussions about expressing the problem in simpler terms and finding a suitable y for any given x. Some participants question how to generalize the approach for all real numbers.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to interpret the problem and suggesting ways to think about the relationship between x and y. There is an exploration of different values and expressions, but no consensus has been reached on a specific method or solution.

Contextual Notes

Participants express confusion about which numbers to input and how to approach the problem without assigning specific values to x and y. The nature of the problem requires a general solution rather than specific numerical examples.

Bucs44
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Here is the problem that I'm having trouble solving - I'm not sure where to begin. I need to determine the truth value but don't know how to do that.

Ax3y(x^2 < y + 1)
 
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Perhaps you could write that out in plain english. It might even help you understand how to solve your problem.
 
For every real number x there exists y, x to the second power is less than y plus 1.

So basically I need to find a number that is less than y + 1
 
No. Read it out loud inserting all of the words.

For all x there is a y such that the condition x^2<y+1 is true.
 
In other words, to prove that true, you must prove that for any given x there exist y such that y+ 1>x2. You need to show that, whatever x is you can find a corresponding y.
 
So if I stated x = 1, then x2 would be 1 and then would or could I say y is 1 as well? Making y + 1=2
 
Now how can you do this for any x?
 
That's what I don't get - I'm not sure what numbers I'm supposed to be inputing here. Please help as I'm really confused
 
After working on this - Is this the answer?

y = x2 + 2x = (x + 1)2 – 1
x < 0 then (x – 1)2 > x2 so y can be x2 – 2x -2
x = 0 then y can be 0
 
  • #10
You're not supposed to put any numbers in that's the point.

Let's play a game. I'm thinking of a number x. Can you give me a number y(possibly in terms of x) so that y+1 is definitely larger than x^2?
 
  • #11
How about z?
 

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