Understanding Newton's Laws: Solving for Forces in Elevator Scenarios

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SUMMARY

This discussion focuses on applying Newton's Laws to analyze forces acting on a 50kg object in an elevator. When the elevator accelerates upwards at 2m/s², the net force acting on the object is calculated using F=ma, resulting in an upward force of 100N. The total force exerted by the elevator on the object, denoted as N, must account for both the gravitational force and the net upward acceleration, leading to the equation N = mg + F_net. This results in a clear understanding of the forces involved when the elevator is in motion versus at rest.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Basic knowledge of force calculations (F=ma)
  • Familiarity with gravitational force (mg)
  • Concept of net force and equilibrium
NEXT STEPS
  • Study the implications of Newton's Second Law in various acceleration scenarios
  • Explore examples of forces in non-inertial reference frames
  • Learn about free-body diagrams and their application in force analysis
  • Investigate the effects of friction and tension in elevator systems
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Students studying physics, particularly those preparing for exams on mechanics, as well as educators seeking to clarify concepts related to forces in accelerating systems.

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Homework Statement


I have this problem which is confusing me a lot! my lecturer isn't very good and I really need to understand this by tomorrow because I got a test.

Let's say there is an object of mass 50kg in an elevator. So, from my knowledge, when this lift is at rest or moving with _uniform_ velocity, the object exerts a 500N on the floor of the lift and the floor of the lift exerts a force of 500N on the object.

However, if the lift is accelerating upwards at 2m/s^2, then the objectis also accelerating which implies that there is a resultant force (F=ma=50*2=100N). This 100N is acting upwards, right? So, now I'm supposed to find the force exerted by the lift on the object and the force exerted by the object on the lift ... if i reasoned correctly, these are equal. How come? Wouldn't the lift move with constant velocity if the 100N resultant force was balanced? :|
 
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Sum up the forces.

At uniform velocity, what is the acceleration?

(1) v=v_0+at

Rearrange it:

(2) \frac{\Delta{v}}{t}=a

Now that you know what the acceleration on the mass is, you can determine the net force on the block:

(3) F=ma

You can combine equations 2 and 3:

(4) m\frac{\Delta{v}}{t}=ma=F

Net force is also given by the summation of forces acting on the block:

(5) F_{net}=N-mg

Now consider the case where the elevator is accelerating upward...

Equation 5 still applies. But this time there is upward acceleration. Use equation 3 to find that net force. Plug it into equation 5 to find N.
 

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