Understanding Parallel Force: Definition, Equation, and Examples

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Parallel force is defined as the component of a force that acts in the same direction as the displacement vector, crucial for calculating work done. The equation for work states that it equals the parallel force multiplied by the distance moved. This means that the parallel force does not need to align with the original surface but must be parallel to the direction of displacement. The parallel force can be calculated using the dot product of the force vector and the unit vector of displacement. Understanding this concept is essential for solving related physics problems accurately.
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It's not a specific problem, but I'm wondering what "parallel force" is defined as.
The equation we were given is work = parallel force x distance.
I was thinking that parallel force is probably the sum of the forces acting in the direction of motion, but some problems we've done in class seem to show otherwise.
Now I'm wondering if parallel force has to be parallel to the original surface?
:confused: I would love if someone could clear this up for me.
 
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A parallel force is the force (or its component) that is parallel to another vector (in this case, displacement). The force has to act parallel to the displacement, not necessarily in the same direction.
 
BrooklynBees said:
It's not a specific problem, but I'm wondering what "parallel force" is defined as.
The equation we were given is work = parallel force x distance.
The work done by a force equals the component of the force parallel to the displacement times the displacement. So "parallel force" means the force in a direction parallel to the displacement direction.
 
The 'parallel' force is given by the dot product

F_{||}=\vec{F}\cdot \hat{r} = |\vec{F}||\hat{r}|\cos{\theta}, where \theta is the angle between the vectors.

In more intuitive terms, you can break the Force vectors into the sum of one that is parallel to the distance vector and one that is perpendicular. For example, if the distance vector is along the x-axis, and the Force vector makes a 30 degree angle with the x-axis, then there will be a parallel force component \vec{F}=|\vec{F}|\cos{30}\hat{x} and a perpendicular force component \vec{F} = |\vec{F}|\sin{30}\hat{y}
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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