Understanding Parallel Resistors in Common-Emitter Amplifiers

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SUMMARY

The discussion focuses on calculating the equivalent resistance of resistors in parallel within a common-emitter amplifier circuit. The specific formula used is for the collector resistance (RC), which combines a collector resistor of 12K ohms and a load resistor (RL) of 50K ohms. The correct calculation yields an equivalent resistance of 9.68K ohms, derived from the formula (50k-1 + 12k-1)-1. Participants confirm the accuracy of this method for determining parallel resistances.

PREREQUISITES
  • Understanding of basic electrical concepts, particularly Ohm's Law.
  • Familiarity with resistor configurations, specifically parallel resistors.
  • Knowledge of common-emitter amplifier circuits.
  • Ability to perform calculations involving resistances and their combinations.
NEXT STEPS
  • Study the principles of Ohm's Law and its applications in circuit analysis.
  • Learn about different resistor configurations, focusing on series and parallel combinations.
  • Explore common-emitter amplifier design and its performance characteristics.
  • Investigate the impact of load resistors on amplifier gain and output impedance.
USEFUL FOR

Electronics students, circuit designers, and engineers interested in amplifier design and resistor calculations will benefit from this discussion.

electrical_ck
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Quick question, i have a formula for finding rc (the ac resistance in the collector circuit) which is rc=RC(collector) is the parallel combination of RL I don't understand that for the example they have RC(collector resistor)= 12K ohms parallel to RL=50k ohms = 9.68K ohms.. someone explain the proper way to get 9.68k? Thanks
 
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Resistors in parallel add this way:

\left( 50k^{-1} + 12k^{-1} \right)^{-1} = 9.68k

- Warren
 
chroot said:
Resistors in parallel add this way:

\left( 50k^{-1} + 12k^{-1} \right)^{-1} = 9.68k

- Warren

yeah I figured it out, just had never seen it in those terms, thanks warren!
 

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