Gajan1234
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There are three Formulas for Power, ( P=IV, P=I^2R, P=V^2/R). Can someone tell me when to use the right forumlas?
The discussion revolves around the appropriate use of three power formulas: P=IV, P=I²R, and P=V²/R. Participants explore the contexts in which each formula is applicable, particularly in relation to electrical circuits and components. The conversation includes elements of theoretical understanding and practical application, with a focus on how different scenarios may dictate the choice of formula.
Participants express a range of views on the appropriate contexts for using each power formula, indicating that there is no consensus on a single correct approach. The discussion remains unresolved regarding the best practices for selecting formulas based on different scenarios.
Participants acknowledge that the formulas can be interchangeable under certain conditions, but the choice often depends on the specifics of the problem presented. There are references to potential confusion arising from textbook explanations and the necessity of understanding each variable's meaning.
This discussion may be useful for students studying electrical engineering or physics, particularly those grappling with the application of power formulas in various contexts.
It is quite confusing in the book as they have used different formula for different question. But I know that P=I^2R is used to find the heatProfuselyQuarky said:How has your textbook explained it?
Okay, well, do you know what each variable stands for?Gajan1234 said:It is quite confusing in the book as they have used different formula for different question. But I know that P=I^2R is used to find the heat
Dale said:What are your thoughts? What is different about the three equations and when might those differences be important?
I for currentProfuselyQuarky said:Okay, well, do you know what each variable stands for?
OK, that is a good start.Gajan1234 said:I think that P=IV is mainly used to find the power of the whole circuit whereas P=I^2R is used to find how much energy is given out by the component per second.
But not sure if I am right.
Dale said:OK, that is a good start.
What is different about P=I^2 R that makes it better for individual components than P=IV?
Right. So would it be possible to use P=I^2 R if you don't know the resistance?Gajan1234 said:Well we are looking at difficulty of current going through due to resistivity.
Not reallyGajan1234 said:But when it come to practice questions it is used differently in different context
Dale said:Right. So would it be possible to use P=I^2 R if you don't know the resistance?
That's correct! See, you can use different equations (in this case, Ohm's Law) to find the missing parts you need. So where's the trouble?Gajan1234 said:Well it is possible if you know the voltage
Yes, exactly. There are only two formulas here: P=IV and V=IR. You have two equations in four variables. You can always substitute one equation into the other to eliminate anyone variable.Gajan1234 said:Well it is possible if you know the voltage
Dale said:Yes, exactly. There are only two formulas here: P=IV and V=IR. You have two equations in four variables. You can always substitute one equation into the other to eliminate anyone variable.
That is all those ewuayions do. You are then left with one equation in three variables. Use the one that fits.
Dale said:Yes, exactly. There are only two formulas here: P=IV and V=IR. You have two equations in four variables. You can always substitute one equation into the other to eliminate anyone variable.
That is all those ewuayions do. You are then left with one equation in three variables. Use the one that fits.
What are the knowns and what are the unknowns? Which formula fits?Gajan1234 said:If you look ag question 3c you can not use all the formulas. Only one will give you the right answer.
And based on that, which formula for power matches what you know?Dale said:What are the knowns and what are the unknowns?
P=v`2/rProfuselyQuarky said:And based on that, which formula for power matches what you know?
This gives me the wrong answerGajan1234 said:P=v`2/r
What numbers did you use?Gajan1234 said:This gives me the wrong answer
Well I can use the P=v^2/R formula but it gives me the wrong answerDale said:What are the knowns and what are the unknowns? Which formula fits?
P=6^2/9ProfuselyQuarky said:What numbers did you use?
Why did you use "6" for volts? The picture's not that clear, but doesn't it read "3"?Gajan1234 said:P=6^2/9
When? Always, always use the right formulas!Gajan1234 said:There are three Formulas for Power, ( P=IV, P=I^2R, P=V^2/R). Can someone tell me when to use the right forumlas?