Understanding Power Series Solutions for Differential Equations

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Homework Help Overview

The problem involves solving a differential equation using power series, specifically the equation y'' + y = x. The original poster expresses confusion regarding the presence of the x term on the right-hand side of the equation and how it affects the coefficients in the power series solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the structure of the power series and how to handle the x term in the equation. The original poster questions how the x fits into the equation for the coefficients cn, particularly in comparison to the simpler case of y'' + y = 0. Others suggest breaking the series into parts and expanding them to group by powers of x.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the series expansion. Some guidance has been offered regarding the need to split the series and consider the x term, but there is no explicit consensus on the approach yet.

Contextual Notes

The original poster identifies themselves as a beginner and expresses uncertainty about using the forum effectively. There is an indication of a lack of familiarity with series, which may affect the discussion's progression.

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Homework Statement



Solve this equation using power series: y'' + y = x



Homework Equations



none

The Attempt at a Solution



I am confused about the x on the RHS of the equation. If the equation was y'' + y = 0, I would have no problem solving it. I am just a little confused about how the x fits into the equation for cn.

if the equation were y'' + y = 0, then cn + 2 = cn/(n+1)(n+2). How does the x fit into this?
 
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You should be able to split up the series you get into three parts. One of those parts will be very short, with just a single term.

Show us what you have for your series.
 
I'm a newb and don't know how to use this website, so here goes:

SUM[ (n+2)(n+1)cn+2xn] + SUM[cnxn] = x
 
[tex] \ \ \sum_{n=0}^{\infty}{(n+2)(n+1)c_{n+2}x^n} \ \ + \ \ \sum_{n=0}^{\infty}{c_{n}x^n} \ \ = x[/tex]

Here it is in the non-retarded version
 
Last edited:
Try expanding your two series and then grouping the results by powers of x. Be sure to take the x on the right side into account.
 
I kind of understand what you're saying, but could you try being a little more specific? I am terrible with series.
 

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