Understanding Prism Deviation Angle in Optics

Click For Summary
Shamim, a high school student, seeks help understanding the prism deviation angle in optics, specifically the formula D = I + r’ – A. He expresses his enthusiasm for physics and his desire to learn. Forum members emphasize the importance of demonstrating prior efforts before seeking solutions, guiding him to relate angles in a triangle to the formula. They suggest using geometry concepts to derive the necessary relationships for understanding the deviation angle. The discussion highlights the supportive nature of the forum while encouraging independent problem-solving.
Shamim
Messages
2
Reaction score
0
1. Dear all
Hello
My name is Shamim and I am a student in high school and having 15 years old. I am a newcomer in this forum. I have found this great forum from internet while I was searching into that. I am really interested too much to physics and actually trying to learn more about that. I wish I can learn this subject as well as I can and learn a lot from you all dear friends. :smile:
This is my first question in this forum. I hope you dear experts can help me and giving me some advise?
Here there is a prism that a light is going through the prism (thick space) from air (thin space). So because of difference density space the light being broken into the prism and again gets broken from prism to thin space (air). If we length the lines from the light from where is coming inside prism and from where it is going out we will make an angle that it shows deviation angle and it gives us a formula as below, according the book said, that I have:

2. (D= I + r’ – A)[/b]
3. Unfortunately I couldn’t demonstrate for myself this formula. :confused: Would you please advise me?
I am thank you very very much in advance.

Best regards
Shamim
 

Attachments

Last edited by a moderator:
Physics news on Phys.org
Hi Shamim, welcome to PF! :smile:
This is really a good place, but there are stick rules. We are not allowed to give full solution to you. And you need to show, what you tried and where you are stuck. Read https://www.physicsforums.com/showthread.php?t=686781, please.

You certainly have learned about triangles and you know that the sum of the interior angles is 180°. You also know what the exterior angles are and an exterior angle is equal to the sum of the two remote interior angles.
You might look at
http://www.wyzant.com/resources/lessons/math/geometry/triangles/angles_of_triangles

Now see the attached picture. Both the incident ray and the deflected ray are extended in the first picture. You get the blue triangle. Find how the angles of the triangle are related to i, r and i', r' and with the exterior angle D. In the second figure, the gray angles are 90°. You find a relation for A, r,, i'. Combining the equations obtained, you get the formula in the book.

ehild
 

Attachments

  • devangle.JPG
    devangle.JPG
    20.1 KB · Views: 542
Last edited:
Dear ehild
So sorry :blushing: Ok, from next time I do the same as you told. :shy: And thank you very very much for your kindness reply and your advise. Very useful to me. :smile: :smile:

Best regards
Shamim
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 207 ·
7
Replies
207
Views
13K