Understanding Relative Motion in Circular Motion

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nysnacc
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Homework Statement


13.164.png


Homework Equations


a= omega^2*r

The Attempt at a Solution


a_A/B = a_A - a_B

a_A = 10^2*r (-î)
a_B = 10^2*r (+ĵ)

a_A/B = 10^2*r (-î) - 10^2*r (+ĵ)
=> -200 î -200 ĵ

why is the answer 200 î -200 ĵ (accelerate in +î direction) ?
 
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nysnacc said:

Homework Statement


View attachment 105735

Homework Equations


a= omega^2*r

The Attempt at a Solution


a_A/B = a_A - a_B

a_A = 10^2*r (-î)
a_B = 10^2*r (+ĵ)

a_A/B = 10^2*r (-î) - 10^2*r (+ĵ)
=> -200 î -200 ĵ

why is the answer 200 î -200 ĵ (accelerate in +î direction) ?
The question is asking for the acceleration of A relative to B. What's the acceleration at A and at B independently?

Hint: Check the direction of acceleration vectors.
 
Last edited:
Student100 said:
The question is asking for the acceleration of A relative to B. What's the acceleration at A and at B independently?

Hint: Check the direction of acceleration vectors.

Err... isn't my expression correct..?

a_A = 10^2*r (-î). A is going -x, -y direction
a_B = 10^2*r (+ĵ). B is going -x, +y direction
 
nysnacc said:
Err... isn't my expression correct..?

a_A = 10^2*r (-î). A is going -x, -y direction
a_B = 10^2*r (+ĵ). B is going -x, +y direction

No. Should your acceleration be tangential or radial to the disk? Remeber the disk has constant angular velocity.
 
Student100 said:
No. Should your acceleration be tangential or radial to the disk? Remeber the disk has constant angular velocity.
should be tangential because constant radius??
 
because constant rotation?
 
so the a_r for B is pointing from point B to Point O
and for A it is pointing from Point A to Point O?
 
nysnacc said:
so the a_r for B is pointing from point B to Point O
and for A it is pointing from Point A to Point O?

Exactly, so what's your relative acceleration now?
 

so the a_r for B is omega^2*r (-i)
a_r for A is omega^2*r (-j)

a_A/B = a_A - a_B = -omega^2*r (j) - -omega^2*r (i)
rearrange = omega^2*r (i) - omega^2*r (j)

Got it! Thanks!