Understanding Simple Harmonic Motion with Position and Acceleration Graphs

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The discussion focuses on sketching a position vs. time graph using an acceleration vs. time graph in the context of simple harmonic motion. It is established that the position graph is a cosine wave while the acceleration graph is a sine wave. Participants clarify that the position graph can be expressed as x = x_0 sin(ωt), indicating a relationship between the two graphs. There is confusion about whether the position graph should be a negative cosine function, which is confirmed to be partially correct but requires adjustment by a constant. Ultimately, the participants reach an understanding of how to relate the two graphs accurately.
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Homework Statement



Using the acceleration as a function of time graph, we are required to sketch the position as function of time graph


Homework Equations


I know that the position vs. time graph is a cosine wave and the aforementioned is a sine wave. I have NO idea how to start considering there are no numbers involved.


The Attempt at a Solution



I tried to plot the point of the a vs time graph corresponding to the position...only 1/4 back. In the end, i got a graph that looked EXACTLY like the first. help?
 
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if a=-\omega^2 x

it is possible to write x as a function of time...x=x_0 sin(\omega t)
 
I think this is meant to be in variables.
http://euclid.hamline.edu/~arundquist/latex/showequation.php?eqn_id=31336
so given the definition of the cosine graph, we know the amplitude and the period.
 
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well since the a vs t graph is a cosine function, wouldn't the x vs. t graph be a negative cosine function? (basically the same thing--inverted?)
 
physks4dumies said:
well since the a vs t graph is a cosine function, wouldn't the x vs. t graph be a negative cosine function? (basically the same thing--inverted?)

correct, though not entirely. the position graph will be adjusted by some constant. take a look at rockfreaks equation, what is it?
 
ooh i understand it now! Thanks eeryone
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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