Understanding Spring Compression: How Doubling It Affects Stored Energy

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If compression of a spring is doubled, the stored energy increased by a factor of?

I think that the stored energy is increased by a factor of 2.

Right?
 
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What is the equation for a spring's potential energy?
 
Fs1=1/2 kx^2 so if k = 25 v=4
= 200

Fs2= k=50 v=4
=400

so by factor of 2
 
Ah, you are doubling the wrong thing. k is the spring constant. The question is asking about changing x by a factor of 2.

[tex]F_{s1} = .5kx^2[/tex]

[tex]F_{s2} = .5k(2x)^2[/tex]

[tex]\frac{F_{s2}}{F_{s1}} = ?[/tex]
 

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