Understanding String Tension in Circular Motion

  • Context: Undergrad 
  • Thread starter Thread starter mr.physics
  • Start date Start date
  • Tags Tags
    String Tension
Click For Summary
SUMMARY

The discussion centers on the concept of string tension in circular motion, specifically when a mass is whirled in a vertical circle. At the top of the swing, tension exists only if the mass is moving faster than the minimum speed required for circular motion; otherwise, tension is zero. If the mass is released from the top with some velocity, the string remains taut due to the combination of gravitational force and the centripetal force needed to maintain circular motion. Understanding these dynamics clarifies why the string does not go slack and the mass does not simply fall under gravity.

PREREQUISITES
  • Understanding of centripetal force and its role in circular motion
  • Basic knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with the concept of tension in strings or ropes
  • Knowledge of projectile motion principles
NEXT STEPS
  • Study the relationship between speed and tension in circular motion
  • Learn about the forces acting on objects in vertical circular motion
  • Explore the concept of minimum speed for circular motion
  • Investigate the effects of releasing objects in motion under gravity
USEFUL FOR

Physics students, educators, and anyone interested in understanding the mechanics of circular motion and the forces involved in string tension dynamics.

mr.physics
Messages
21
Reaction score
0
Hi there,

I have a very basic question about string tension. Say I have a mass at the end of some string whirled around in a vertical circle. At the top of the swing why is there still tension? I get that if the speed of the mass is large enough some tension would be needed to supply the centripetal force, but I don't understand why the tension would act in response to the "needs" of the centripetal force. It seems to me there would only be tension if the mass were trying to move farther away from the center of the circle than allowed by the string. If I were to release the mass in this same configuration from the top of the swing with some velocity, why isn't the string just slack and why doesn't the mass just fall down in response to gravity?

Thanks for the help
 
Physics news on Phys.org
It depends how fast you are twirling it. If you twirl it with the minimum rotation necessary to make a circle, then the tension at the top is 0. But if you twirl any faster, then the string is pulling on the mass to accelerate the mass downward faster than free-fall. In the absence of forces, the mass will just travel in free-fall. Not sure what is confusing you.

If you release the mass in the same configuration, you get the same behavior, of course. You are launching the mass horizontally, but your string is attached vertically, so the mass isn't free to travel horizontally, but is pulled by the string downward.
 
mr.physics said:
Hi there,

I have a very basic question about string tension. Say I have a mass at the end of some string whirled around in a vertical circle. At the top of the swing why is there still tension? I get that if the speed of the mass is large enough some tension would be needed to supply the centripetal force, but I don't understand why the tension would act in response to the "needs" of the centripetal force. It seems to me there would only be tension if the mass were trying to move farther away from the center of the circle than allowed by the string. If I were to release the mass in this same configuration from the top of the swing with some velocity, why isn't the string just slack and why doesn't the mass just fall down in response to gravity?

Thanks for the help

Try not to think anthropomorphically. There is a constant acceleration downwards due to gravity, in addition to anything caused by the string. So, at the top, in the limiting case, there is just enough centripetal acceleration (g) to keep the motion in a circle and the tension would be zero. If the mass were going any slower then g would be more centripetal acceleration than needed to keep the circular motion and the mass would follow a parabola - not a circle.
 

Similar threads

Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 19 ·
Replies
19
Views
15K
Replies
46
Views
7K
  • · Replies 3 ·
Replies
3
Views
9K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K