Understanding the Circle Equation: Explained Simply | Roger's Guide

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The discussion focuses on understanding the circle equation, specifically x² + y² = R², which represents a circle centered at the origin with radius R. A circle is defined as the set of all points equidistant from a center point, and the distance from the origin to any point (x, y) can be calculated using the Pythagorean theorem. To visualize the equation, plotting a unit circle (x² + y² = 1) is suggested, where specific values for x and y yield key coordinates. The conversation emphasizes the importance of grasping both the geometric definition and the algebraic representation of circles. Overall, the thread aims to clarify the concept of circles in mathematics.
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Hi

we are learning the circle equation now, but I don't understand it at all :confused:

Please can someone explain the equation in a simple way ?

thanks a lot !

Roger
 
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Are you talking about:
x^{2}+y^{2}=R^{2}
or some different creature?
Be more specific; post the equation you're confused about!
 
Dear Arildno,

Yes that's the equation which I mean.

there's also different variations on it as well with other terms.
please can you help me


Roger
 
Do you know the geometric definition of a circle?
 
the definition of a circle is the locus of all points equidistant from a given point.

x^2 + y^2 = r^2 is the equation of a circle with radius r, and center at (0,0)

(x-h)^2 + (y-k)^2 = r^2 is the equation of a circle with center (h,k)

Then we also have general equation of conic.
 
Hurkyl said:
Do you know the geometric definition of a circle?

No I don't.

I don't actually understand the equation or definition ...Thats the problem.

Arildno mentioned the equation but please can someone explain for me .
Thanks

Roger
 
A circle can be considered the set of all point that have a certain distance (the radius) from a certain point (the center).

In above case the center is the origin (0,0) and the distance is R. Thus, the cirlce is the set of all points (x,y) which have a distance R from the origin. The distance of a point (x,y) from the origin is sqrt(x² + y²) using Pythagoras, so your condition for a point to be part of the circle is
sqrt(x² + y²) = R
or, when squaring that equation:
x² + y² = R²
 
Have you tried plotting a "unit circle" on a graph? You can use the equation
x^2 + y^2 = 1

if you let y = 0, then you have two possible solutions for x: 1 and -1
this will give you some coordinates: (1,0) and (-1,0)
if you let x = 0, then you have two possible solutions for y: 1 and -1
this will give you some coordinates: (0,1) and (0, -1)

you can play around with plugging in other numbers between zero and 1 for x and y, and if you plot these, you should see a circle forming on your graph.
I don't know if this will be helpful to you, but I remember going through this exercise when I studied trig and it helped me visualize how this function worked.
 

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