Understanding the Concept of "y=mx+b

[cookiemonster]

2's the right answer, whether by elimination or thinking it out, nobody cares? ;)

For reference, a vertical or horizontal line will be in only two quadrants. For example, if m = 0 and b = 1, we have the line

y = 1

which is only in the first and second quadrants.

Stem cell research, eh? I guess I can have a look...

cookiemonster

 

[ahrkron]

I noticed that this thread has changed subject a couple times. There is no hard policy on this, but information will later be easier to find if we use new threads for new subjects.

My point is that, if you have some other, new question, feel free to open a new thread (unless, of course, it is closely related to this one).

 

[Imparcticle]

For reference, a vertical or horizontal line will be in only two quadrants.

cookiemonster

But you never said a vertical/horizontal line; you said non-vertical and non horizontal. Lines can be diagonal too. But I guess it was my folly here; I didn't ask specifically.

thanks so much!

Sorry about that arhkron.

 

[cookiemonster]

Ah, sorry. I remember saying not to consider vertical lines because the equation to describe them doesn't work like you normally expect y = mx + b to.

Anyway, I mean that only vertical or horizontal lines will be in two quadrants. If a line is diagonal in the slightest, it will end up in three quadrants. Except for maybe lines that pass through the origin...

cookiemonster