Understanding the Conventional Current Flow in Circuit Components

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The discussion clarifies the roles of the anode and cathode in diodes, emphasizing that the anode is where current enters and the cathode is where it exits. It explains that in a forward-biased pn junction, a positive voltage is applied to the p-side, causing positive charges to move towards the n-side, which acts as the cathode. The terms anode and cathode can vary based on whether the device is active or passive, affecting their polarity. The confusion arises from the distinction between conventional current flow and electron flow. Understanding these definitions is crucial for accurately interpreting circuit behavior.
sanado
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Hey guys, was sitting through a physics class today and something bothered me. They referred to the p material of a diode as being the anode and the n material being a cathode. Being a chemistry student I am aware that the cathode is + while the anode is -ve. Why has it changed around, due to the use of conventional current? Or is it because of the electric field in the depletion layer?
 
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Hi sanado,

I don't think it is correct to say that the cathode is positive and the anode is negative. The anode is where the current is entering the device, and the cathode is where the current is leaving the device. (For example, if you are using a battery, the negative terminal is the anode, but if you are recharging the battery the positive terminal is the anode.)

For the cathode side of a pn junction: When you forward bias a pn junction to get current to flow, you attach a positive voltage to the p side. This causes the extra positive charges (the holes) in the p side to move away to the n side, where they exit the crystal. Since the positive current leaves the n side, the n side is the cathode.
 
You are right, alphysicist. For any device, electrons flow out of the anode and conventional current flows out of the cathode. Which is the positive side and which is the negative side will depend on whether it's an active device like a voltage source (cathode positive, anode negative) or a passive device like a diode (anode positive, cathode negative).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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