Understanding the Del Operator in Vector Calculus

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The discussion focuses on proving the equation (û⋅∇)F=û, where F is a vector from the origin to a point (x,y,z) and û is a unit vector. Participants clarify that û can be expressed as a combination of its components in the x, y, and z directions, making û⋅∇ a scalar operator. They emphasize that evaluating the expression with the given vector F should not be difficult. One participant initially struggles but later confirms they have solved the problem, indicating a learning experience. The conversation highlights the importance of clear communication and sharing steps in problem-solving for effective assistance.
namnimnom
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F is a vector from origin to point (x,y,z) and û is a unit vector.
how to prove?
(û⋅∇)F

only tried expanding but it's going nowhere
 
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If ##\hat u = u_x \hat x + u_y \hat y + u_z \hat z##, then you have
$$
\hat u \cdot \nabla = u_x \partial_x + u_y \partial_y + u_z \partial_z
$$
which is a scalar operator. With ##\mathbf F = x \hat x + y \hat y + z \hat z##, I don't see why it's difficult to evaluate ##(\hat u \cdot \nabla) \mathbf F##.
 
Hello nnn, :welcome:
namnimnom said:
only tried expanding but
This does not help us to help you effectively. In such a case you should write down your expansion so we can provide better assistance to overcome the hurdle you are experiencing. Or did it help you to read that it isn't difficult :rolleyes: ?
 
blue_leaf77 said:
If ##\hat u = u_x \hat x + u_y \hat y + u_z \hat z##, then you have
$$
\hat u \cdot \nabla = u_x \partial_x + u_y \partial_y + u_z \partial_z
$$
which is a scalar operator. With ##\mathbf F = x \hat x + y \hat y + z \hat z##, I don't see why it's difficult to evaluate ##(\hat u \cdot \nabla) \mathbf F##.

BvU said:
Hello nnn, :welcome:
This does not help us to help you effectively. In such a case you should write down your expansion so we can provide better assistance to overcome the hurdle you are experiencing. Or did it help you to read that it isn't difficult :rolleyes: ?

solved it. I'm probably TOO new to this hahahha thank you! :)
 

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