Understanding the Del Operator in Vector Calculus

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    Del Operator
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Homework Help Overview

The discussion revolves around the application of the del operator in vector calculus, specifically in the context of evaluating the expression \((\hat{u} \cdot \nabla) F\) where \(F\) is a vector field. Participants are exploring the implications of using a unit vector \(\hat{u}\) in this operation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the representation of the unit vector \(\hat{u}\) and its relation to the del operator. Some express confusion about the evaluation of the expression \((\hat{u} \cdot \nabla) F\) and seek clarification on the steps involved in the expansion.

Discussion Status

The conversation includes attempts to clarify the mathematical representation of the del operator and its application. Some participants have provided insights into the nature of the operator, while others have expressed the need for more detailed explanations or examples to aid understanding.

Contextual Notes

There is a mention of the original poster's struggle with the problem, indicating a potential gap in understanding the underlying concepts. The discussion reflects varying levels of familiarity with vector calculus among participants.

namnimnom
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Member advised to use the formatting template for all homework help requests
F is a vector from origin to point (x,y,z) and û is a unit vector.
how to prove?
(û⋅∇)F

only tried expanding but it's going nowhere
 
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If ##\hat u = u_x \hat x + u_y \hat y + u_z \hat z##, then you have
$$
\hat u \cdot \nabla = u_x \partial_x + u_y \partial_y + u_z \partial_z
$$
which is a scalar operator. With ##\mathbf F = x \hat x + y \hat y + z \hat z##, I don't see why it's difficult to evaluate ##(\hat u \cdot \nabla) \mathbf F##.
 
Hello nnn, :welcome:
namnimnom said:
only tried expanding but
This does not help us to help you effectively. In such a case you should write down your expansion so we can provide better assistance to overcome the hurdle you are experiencing. Or did it help you to read that it isn't difficult :rolleyes: ?
 
blue_leaf77 said:
If ##\hat u = u_x \hat x + u_y \hat y + u_z \hat z##, then you have
$$
\hat u \cdot \nabla = u_x \partial_x + u_y \partial_y + u_z \partial_z
$$
which is a scalar operator. With ##\mathbf F = x \hat x + y \hat y + z \hat z##, I don't see why it's difficult to evaluate ##(\hat u \cdot \nabla) \mathbf F##.

BvU said:
Hello nnn, :welcome:
This does not help us to help you effectively. In such a case you should write down your expansion so we can provide better assistance to overcome the hurdle you are experiencing. Or did it help you to read that it isn't difficult :rolleyes: ?

solved it. I'm probably TOO new to this hahahha thank you! :)
 

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