Understanding the Derivation of the Latent Heat and Entropy Equation

Click For Summary

Homework Help Overview

The discussion revolves around the derivation of the equation relating latent heat and entropy, specifically the expression ##L / T = \Delta S##. Participants are exploring the definitions and relationships between latent heat, specific latent heat, and entropy changes in thermodynamic contexts.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the relationship but encounters confusion regarding the definitions of latent heat and specific latent heat. Some participants suggest examining the dimensions of the variables involved and question the mixing of total and specific quantities.

Discussion Status

The discussion is ongoing, with participants providing guidance on the importance of distinguishing between total and specific quantities. There is an exploration of the implications of these distinctions on the original poster's understanding of the equation.

Contextual Notes

Participants note the potential confusion arising from using different forms of heat (total vs. specific) and emphasize the need for clarity in definitions when discussing thermodynamic equations.

WWCY
Messages
476
Reaction score
15

Homework Statement


I came across this equation ##L / T = \Delta S## and am not too sure about its derivation.

From what I know, ##L = Q/m## and ##Q = TdS ##.

Substitution gives me ##\Delta S = mL / T## which isn't correct.

Could someone assist me in understanding the derivation?

Thanks!

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
WWCY said:
Could someone assist me
Look at the dimensions of your variables
 
WWCY said:
From what I know, L=Q/m and Q= TdS .
That's giving you dS as the total entropy change of the sample, but L as the specific latent heat (i.e. per unit mass). You're comparing apples and oranges, no wonder you don't get a sensible answer.
What do you know, in terms of energetics, about the equilibrium at the melting point?
 
mjc123 said:
That's giving you dS as the total entropy change of the sample, but L as the specific latent heat (i.e. per unit mass).

Am I mixing latent heat (total heat) with specific latent heat (heat / unit mass)?
 
Yes. work with total quantities (not usually useful for a general statement like your equation), or specific quantities, or molar quantites, but don't mix them up. It looks like you're just quoting formulae without understanding them.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K