Understanding the Equation for Waves on a String: Help Needed!

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The discussion focuses on interpreting the wave equation y = (15cm)cos(πx/5.0cm - πt/12s) and sketching it for t = 0. A participant struggles with the notation and calculations, initially obtaining incorrect values for y. Another contributor clarifies that the issue arises from using degrees instead of radians in calculations. By correctly applying the equation with x values, they demonstrate how to find accurate y values, emphasizing the importance of using the correct angle measurement. The conversation highlights common pitfalls in understanding wave equations and the significance of proper calculation methods.
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Homework Statement



A wave on a string is described by the following equation: y = (15cm)cos(πx/5.0cm - πt/12s). Sketch this wave from x = 0 to x = 10 cm for the t = 0.



The Attempt at a Solution


Honestly, I've never seen this notation before. I have no idea how to interpret it. I tried googling some help and now I'm more confused. I tried setting t to 0 and putting different values for x in order to get a value for y, but I get 14.9... for every value of x, which gives me a straight line, and that answer was incorrect. It might be hard to explain this online, but I would appreciate it immensely if somebody would please try. I'm utterly lost.
 
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Then you are doing something wrong in your calculations or choosing to few x's.
For instance, if x = 0 then y = 15, if x = 2,5 then y = 0, if x = 5 then y = -15 and so on.
How are you doing the calculations?
 
This is what I am doing:

Using x=2.5 for example,

t=0, so...
15 x cos[(pi*2.5)/5.0 - (pi*0)/12]
15 x cos(1.57 - 0)
15 x 0.9996 = 14.99

I'm obviously doing something wrong, because I know for x=2.5 y should equal 0
 
your calculator is set to degrees, it should be set to radians.
 
Omg...I feel like a complete moron.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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