Understanding the Magnetic Constant: Finding the Force Between Two Magnet Poles

  • Thread starter Thread starter winkZ
  • Start date Start date
  • Tags Tags
    Constant Magnetic
Click For Summary
SUMMARY

The discussion focuses on calculating the force between two magnetic poles with strengths of 40 amp-m and 50 amp-m at a distance of 10 cm. The magnetic constant provided by the professor, 107 N/Amp2, is identified as the permeability of free space, which is not appropriate for this calculation. The correct formula for magnetic force is F = (constant(q1)(q2))/(distance2), and a computational error was noted in the initial attempt, specifically regarding the distance conversion from centimeters to meters.

PREREQUISITES
  • Understanding of magnetic poles and their strengths
  • Familiarity with the formula for magnetic force
  • Knowledge of the permeability of free space
  • Basic unit conversion (cm to m)
NEXT STEPS
  • Research the correct value of the permeability of free space (μ0)
  • Learn about the differences between magnetic and electric forces
  • Study the application of Coulomb's Law in electrostatics
  • Explore common computational mistakes in physics calculations
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to magnetic forces and constants.

winkZ
Messages
2
Reaction score
0

Homework Statement


Hi. I don't have any physics book at the moment. This has something to do with magnets&magnetic poles:

What is the force between two magnet poles of strengths 40amp-m and 50amp-m at a distance of 10cm in the air?

This sounds easy, but my problem is I don't know the magnetic constant to use. Our professor said the constant is 10^7N/Amp^2. But, I don't think its correct since he wasnt sure about it too. I tried to look for it in the net, but I can find nothing with that value...

Thanks


Homework Equations



Also, our professor told us that the formula is: F = (constant(q1)(q2))/(distance^2)



The Attempt at a Solution



so using the constant he gave us

F = (10^7N/A^2)(40amp-m)(50amp-m)/(0.10m)^2
F= 10^7(40)(50)N

Which seems correct, but I'm not sure about the value of the constant...

thanks :D
 
Physics news on Phys.org
winkZ said:
so using the constant he gave us

F = (10^7N/A^2)(40amp-m)(50amp-m)/(0.10m)^2
F= 10^7(40)(50)N

The constant he gave you is the http://en.wikipedia.org/wiki/Permeability_%28electromagnetism%29" .
Basically a measure of how "easily" a material (in this case vacuum) can support a magnetic field.

However it should be used in place of the Permittivity of free space you find in Coulomb's Law for electrostatics.

There appears to be a second (computational) mistake in your calculation as well.
 
Last edited by a moderator:
Onamor said:
The constant he gave you is the http://en.wikipedia.org/wiki/Permeability_%28electromagnetism%29" .
Basically a measure of how "easily" a material (in this case vacuum) can support a magnetic field.

However it should be used in place of the Permittivity of free space you find in Coulomb's Law for electrostatics.

There appears to be a second (computational) mistake in your calculation as well.
thanks...a lot... i think i forgot the 0.01 :D thanks :D
 
Last edited by a moderator:

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
1K
  • · Replies 23 ·
Replies
23
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
3K
  • · Replies 25 ·
Replies
25
Views
6K