Understanding the Relationship Between Force and Momentum: F=dp/dt Explained

  • Context: Undergrad 
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Discussion Overview

The discussion centers around the relationship between force and momentum, specifically the equation F=dp/dt. Participants explore the theoretical foundations, historical context, and implications of this relationship in both classical and modern physics. The conversation includes mathematical derivations, conceptual clarifications, and differing interpretations of the equation's significance.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants explain the derivation of F=dp/dt using the chain rule and the relationship between momentum and mass-velocity.
  • Others argue that F=dp/dt is a definitional equation in modern physics, contrasting it with the historical formulation of F=ma.
  • A participant emphasizes that Newton originally expressed force as F=d(p)/dt, suggesting this formulation is more fundamental than F=ma.
  • Concerns are raised about the Galilean invariance of the equations, with some arguing that F=ma is simpler and more universally applicable than F=dp/dt.
  • Some participants highlight the importance of considering mass variation in certain systems, such as rockets, where F=dp/dt is necessary for accurate modeling.
  • A later reply questions the need for a solid proof of F=dp/dt, suggesting that its validity as a scientific statement should be logically consistent.

Areas of Agreement / Disagreement

Participants express differing views on the foundational nature of F=dp/dt versus F=ma, with no consensus reached on which formulation is more fundamental or universally applicable. The discussion remains unresolved regarding the implications of mass variation and the necessity of each equation in different contexts.

Contextual Notes

Participants note that the discussion involves assumptions about mass conservation and the applicability of classical mechanics versus modern physics frameworks. The implications of relativistic effects on the equations are also mentioned, indicating a complexity that is not fully resolved within the discussion.

  • #61
What's the lagrangian you're using?
 
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  • #62
Physics Monkey said:
This factor is important because it allows you to set the rest of the integrand to zero (in general, just because the integral of a function is zero doesn't mean the function is zero). Hope this helps.
By the way, you wouldn't happen to go to Georgia Tech would you?
Thanks for the part in bold, I was actually looking at what I'd written after wondering why it wasn't \delta{S} = constant.
As for your question, I go to NUI Maynooth in Ireland.
What's the lagrangian you're using?
A general one for a conservative force.
 

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