John_Doe
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What's the lagrangian you're using?
Thanks for the part in bold, I was actually looking at what I'd written after wondering why it wasn't \delta{S} = constant.Physics Monkey said:This factor is important because it allows you to set the rest of the integrand to zero (in general, just because the integral of a function is zero doesn't mean the function is zero). Hope this helps.
By the way, you wouldn't happen to go to Georgia Tech would you?
A general one for a conservative force.What's the lagrangian you're using?