Understanding the Right Hand Rule: Vector (AxB)

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To apply the right hand rule for the vector cross product (AxB), it's essential to redraw the vectors so their tails meet at the same point. This adjustment allows for a proper visualization of the angle between the vectors. The direction of the resulting vector is determined by the orientation of the fingers when the hand is positioned according to the right hand rule. Redrawing does not alter the vectors themselves; it merely facilitates the application of the rule. Understanding this technique is crucial for correctly determining the direction of the cross product.
duplaimp
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Hi,
I have a question about how to apply the right hand rule in this vector (AxB)

5PNOAT8.png


I would say that it is -k (missing ^) because of the smallest angle is the one drawn in red, but it is k. Can anyone explain why?
 
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Draw the vectors with their tails at the same point.
 
But the vectors are given as I draw
 
duplaimp said:
But the vectors are given as I draw
True, but you must redraw them to properly apply the right hand rule. The vectors are both applied at the same point; redraw so that the tails of the vectors emanate from that point.

By redrawing the vectors you are not changing them. You're just sliding the vector A over so that its tail coincides with that of vector B. Sliding vectors around does not change them, as long as they continue to point in the same direction.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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