Understanding Vector Calculus Proof: Divergence Theorem and Scalar Field

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
physiks
Messages
101
Reaction score
0
The following is used as part of a proof I'm trying to understand:

Vf(.A)dV=∫SfA.dS-∫VA.(f)dV
where f is a scalar field, and the surface integral is taken over a closed surface (which presumably encloses the volume).

I'm not sure how to go about proving this. I can see the divergence theorem will come into play at some stage, but the scalar field seems to be in the way to start with. This is probably really simple, I'm a little rusty with my vector calculus.

Clues would be helpful, thanks :)
 
Physics news on Phys.org
Hi physiks,
Rewrite your expression like $$\int_V f(\nabla \cdot \mathbf{A}) + \mathbf{A} \cdot (\nabla f)\, dV = \int_S f\mathbf{A} \cdot \mathbf{dS}$$ and work with the left hand side to show the right hand side.
 
CAF123 said:
Hi physiks,
Rewrite your expression like $$\int_V f(\nabla \cdot \mathbf{A}) + \mathbf{A} \cdot (\nabla f)\, dV = \int_S f\mathbf{A} \cdot \mathbf{dS}$$ and work with the left hand side to show the right hand side.

Got it, thanks!