Understanding Vector Equations in Homework Problems

  • Thread starter Thread starter quietrain
  • Start date Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
quietrain
Messages
648
Reaction score
2

Homework Statement


electrotut2.png


Homework Equations


electrotut.png

The Attempt at a Solution



can anyone enlighten me what the red and blue equations mean? i remembered something about the red eqn meaning unit vector in vector format, or scalar format is it?

and the blue eqn i have totally no idea what my prof is doing >< is he trying to say that del F is a dot product and since they are 0 because i =/= j, that means that cross product is 0?

help appreciated!
 
Last edited:
Physics news on Phys.org
hi quietrain ! :smile:

it's all very simple …

r^/r2 = (r/|r|)/r2 = r/r3

and

∂/∂xi (Fj)

= ∂/∂xi (xj)

= ∂/∂xi (xj/r3)

= {∂/∂xi (xj)}/r3 + {∂/∂xi 1/r3)}xj (product rule)

= 0 + {∂/∂xi 1/r3)}xj :wink:
 
with regards to part b)

for the cross product (del X F) to be 0, are they saying that delyFz - delzFy must be 0 and the other permutations too,

so that delyFz = delzFy

but from the form ∂/∂xi (Fj), it has a minus sign after differientiating, thus for Eijk, if we swop once to Eikj , then the minus sign is gone

so now its minus - plus = 2 minus , not 0?
 
hi quietrain! :smile:

(have a del: ∇ and an epsilon: ε :wink:)
quietrain said:
for the cross product (del X F) to be 0, are they saying that delyFz - delzFy must be 0 and the other permutations too,

so that delyFz = delzFy

yes :smile:
but from the form ∂/∂xi (Fj), it has a minus sign after differientiating, thus for Eijk, if we swop once to Eikj , then the minus sign is gone

so now its minus - plus = 2 minus , not 0?

ah, you can either write ∇jFk - ∇kFj

or εijkjFk

same thing :wink:
 
tiny-tim said:
hi quietrain! :smile:

(have a del: ∇ and an epsilon: ε :wink:)


yes :smile:


ah, you can either write ∇jFk - ∇kFj

or εijkjFk

same thing :wink:


oh so it becomes minus minus minus which is minus plus = 0
thanks!